The answer is A.
D= 6<=x<=11
Using the dot product:
For any vector x, we have
||x|| = √(x • x)
This means that
||w|| = √(w • w)
… = √((u + z) • (u + z))
… = √((u • u) + (u • z) + (z • u) + (z • z))
… = √(||u||² + 2 (u • z) + ||z||²)
We have
u = ⟨2, 12⟩ ⇒ ||u|| = √(2² + 12²) = 2√37
z = ⟨-7, 5⟩ ⇒ ||z|| = √((-7)² + 5²) = √74
u • z = ⟨2, 12⟩ • ⟨-7, 5⟩ = -14 + 60 = 46
and so
||w|| = √((2√37)² + 2•46 + (√74)²)
… = √(4•37 + 2•46 + 74)
… = √314 ≈ 17.720
Alternatively, without mentioning the dot product,
w = u + z = ⟨2, 12⟩ + ⟨-7, 5⟩ = ⟨-5, 17⟩
and so
||w|| = √((-5)² + 17²) = √314 ≈ 17.720
Answer:
Look below
Step-by-step explanation:
Ok Just Plug it in
For the chart
1:8
2:9
3:10
4:11
And then graph on desmos
You should the answer
Sorry if I am wrong.
H=number of hours
m=total salary
m=15.50h+50
put 400 in for m
400=15.50h+50
now solve for h
400=15.50h+50
-50. -50
350=15.50h
Divide 350 by 15.50to get your final answer
you get a long decimal so I rounded it.
22.6 hours
Answer:
Each students provides 13 pounds of meal
Step-by-step explanation:
Total students in Ms. Lee class = 220
Total pounds of food collected = 2,860
how many meals did each student provide?
Meals provided by each student = Total pounds of food collected / total number of students
= 2,860 / 220
= 13 pounds
Each students provides 13 pounds of meal
Note: 1.2 pounds of food equals one meal
1.2 pounds : 1 meal = 13 pounds : x meals
1.2/1 = 13/x
1.2 * x = 1 * 13
1.2x = 13
x = 13 / 1.2
= 10.83 meals
Approximately 11 meals to the nearest number
Note:1 kilogram is 2.2 pounds
1 kg : 2.2 pounds = x kg : 13 pounds
1/2.2 = x / 13
1 * 13 = 2.2 * x
13 = 2.2x
x = 13/2.2
= 5.91 kilogram
Approximately x = 6 kilograms
