The nickels in the envelope is $0. 12
<h3>How to determine the number</h3>
From the information given, we have that;
Dimes + nickels = $1. 20
1/4 dimes + dimes = $ 1. 35
Let dimes = d
Nickels = n
d + n = 1. 20 equation a
d/4 + d = 1. 35 equation b
Make 'd' subject from equation a
d = 1. 20 - n
Substitute into equation b
1. 20 - n/ 4 + 1. 20 - n = 1. 35
0. 3 - 0. 25n + 1. 20 - n = 1. 35
collect like terms
- 1. 25n = 1. 35 - 1. 5
- 1. 25 = - 0. 15
n = -0. 15/ -1. 25
n = 0. 12
Thus, the number of nickels in the envelope is $0. 12
Learn more about algebraic expressions here:
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Answer:
29
Step-by-step explanation:
full angle of a triangle is 180 and 34+177=151 then you just do 180-151=29.
M’(2, 3)
Work:
x: -1 + 3 = 2
y: 5 - 2 = 3
Option D:
![d=\sqrt{(19+1)^2+(20+1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2819%2B1%29%5E2%2B%2820%2B1%29%5E2%7D)
Explanation:
Given data:
The points are (–1, –1) and (19, 20).
<u>To find the distance between two points:</u>
![x_1=-1, y_1=-1, x_2=19, y_2=20](https://tex.z-dn.net/?f=x_1%3D-1%2C%20y_1%3D-1%2C%20x_2%3D19%2C%20y_2%3D20)
Distance formula:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
![d=\sqrt{(19-(-1))^2+(20-(-1))^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2819-%28-1%29%29%5E2%2B%2820-%28-1%29%29%5E2%7D)
![d=\sqrt{(19+1)^2+(20+1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%2819%2B1%29%5E2%2B%2820%2B1%29%5E2%7D)
Hence option D is the correct answer.