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romanna [79]
3 years ago
11

Am I correct if not what is the correct answer

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer: yes you are right

Step-by-step explanation:

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Please Help! First answer will be marked as Brainliest The table compares the height of a table and the height of the chairs (bo
kakasveta [241]

Answer:

Yes.

Step-by-step explanation:

If you write out the coordinates, you can see that you can do the Vertical Line Test and confirm that if you were to write a function, it would be an actual function. No 2 x-values can be the same y-values. The coordinates all have separate xy values (or the same exact xy values) and you can determine a function.

4 0
3 years ago
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Find the value of x then tell whether the side lengths form a Pythagorean triple 6 , 10 , x
masya89 [10]

Answer:

Explanation:

Use the Pythagorean theorem (

a

2

+

b

2

=

c

2

)

Lets label the right triangle such that:

a

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12

b

=

16

c

=

x

Thus,

12

2

+

16

2

=

x

2

144

+

256

=

x

2

400

=

x

2

√

400

=

x

20

=

x

So our missing side,

c

is

20

We can now say that the sides of our triangle are

12

,

16

,

20

I've included a link that lists a couple of Pythagorean triples (a couple because they are infinitely many).

Step-by-step explanation:

Hope it helpful

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2 years ago
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Solve for x. <br><br> a²x+(a-8)=(a+8)x
Sergio [31]
a^2x+(a-8)=(a+8)x\\\\(a+8)x=a^2x+(a-8)\ \ \ \ |subtract\ a^2x\ from\ both\ sides\\\\(a+8)x-a^2x=a-8\\\\(a+8-a^2)x=a-8\ \ \ \ |divide\ both\ sides\ by\ (a+8-a^2)\\\\\huge\boxed{x=\frac{a-8}{a+8-a^2}}\to\huge\boxed{x=\frac{8-x}{a^2-a-8}}
6 0
3 years ago
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MORE MATH GENIUSES!!!!!!!!!!!!!!
Oliga [24]

Answer:

The friend caught the ball at 2 feet.

Step-by-step explanation:

1. False; the ball was not still in the air at 1 second the x-component of the vertex is 0.5.

2. False; the x-component of the vertex is 0.5

3. True; the ball was tossed at a height of 2 feet (when x=0, y=2), it is safe to assume the ball was caught at the same height.

4. False; when x = 0, y = 2.

8 0
3 years ago
I need help with the following picture​
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Answer:

A

Step-by-step explanation:

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