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Ugo [173]
3 years ago
11

Please help ASAP !! Via the photo below

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0

Answer:

y-3 = -4 (x-1)

Step-by-step explanation:

y= -4x - 5

In slope-intercept form, they give us the slope, -4, and the y-intercept, -5 (we don't need for point-slope form).

Use the point (1,3) and substitute it into the equation.

Point-slope form: y-y1 = m(x-x1)

y-3 = -4 (x-1)

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1. The amount of money Travis earns is given in the table.
Anastaziya [24]

Answer:

  $250

Step-by-step explanation:

The numbers in the table indicate a proportional relationship between earnings and hours worked. Among other things, that means you can find the earnings for 20 hours by using any table values that sum to 20 hours.

For example, 9 hours + 11 hours = 20 hours, so the earnings would be ...

  $112.50 +137.50 = $250.00 . . . for 20 hours

You could also use 4×5 hours = 20 hours, so ...

  4×$62.50 = $250 . . . for 20 hours

__

Or, you can figure ...

  $37.50/(3 h) = $12.50/h

so the pay for 20 hours is ...

  (20 h)×($12.50/h) = $250.00

3 0
2 years ago
Read 2 more answers
1. M is the midpoint of LN and O is the midpoint of NP.
Reptile [31]
1. M is the midpoint of LN and O is the midpoint of NP. This makes the triangle MNO equal to half of LNP. Then you can get this equation
MO= (1/2) LP

If you insert MO = 2x +6 and LP = 8x – 20 the calculation would be:
2x+6= (1/2)( 8x-20)
2x+6= 4x-10
2x-4x= -10 - 6
-2x= -16
x=8

2. Centroid is the point that intersects with three median lines of the triangle. The centroid should divide the median lines into 1:2 ratio. In AC lines, A located in the base so A.F:FC would be 1:2

Then, the answer would be:
A.F= 1/(1+2) * AC
A.F= 1/3 * 12= 4

FC= 2/(1+2) * AC
FC= 2/3 * 12= 8

3. Since
∠BAD=∠DAC
∠ABD=∠ACD
AD=AD
The triangle ABD and ACD are similar. You can get this equation
BD=DC
x+8= 3x+12
x-3x= 12-8
-2x=4
x=-2

DC=3x+12= 3(-2) +12= 6

4. Orthocenter made by intersection of triangle altitude
A
BC lines slope would be (-4)-(-1)/1-4= -3/-3= 1. The altitude line slope would be -1, the function would be:
y=-x +a
0= 1+a
a=-1
y=-x-1
B
AC lines slope would be (-4)-(-1)/1-0= -3. The altitude line slope would be 1/3, the function would be:
y=1/3x+a
-1=1/3(4)+a
a=-7/3
y=1/3x - 7/3

C
BC lines slope would be (-1)-(-1)/4 = 0/4. 
The line would be 
0=x+a
a=-1
0=x-1
x=1

y=-x-1 = 1/3x-7/3
-x-(1/3x)=-7/3 +1
-4/3x= -4/3
x=1

y=-x-1
y=-1-1= -2
The orthocenter would be (1,-2)

5. 
a. Circumcenter: the intersection of perpendicular bisector lines<span>
b. Incenter: the intersection of bisector lines
c. Centroid: </span>the intersection of median lines<span>
d. Orthocenter: </span>the intersection of altitude lines
5 0
2 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
2 years ago
Which manner identifies a way that a mammal can be born?
aliya0001 [1]
Mammals are almost always born live from the mother.
6 0
3 years ago
Help me I need the answer to #2 and #4
Karo-lina-s [1.5K]
Number 2 is 84.13
number 4 is 56
3 0
2 years ago
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