3 years ago

Use the following function rule to find f(1). f(x) = (2)* f(1) = | Submit

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

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<img src="https://tex.z-dn.net/?f=0.2%2810-5c%29%20%3D%205c%20-%2016" id="TexFormula1" title="0.2(10-5c) = 5c - 16" alt="0.2(10-

san4es73 [151]

We are given,

$\longrightarrow 0.2(10 - 5c) = 5c - 16$

Solving the parenthesis

${ \longrightarrow 0.2 \times 10 - 0.2 \times 5c = 5c - 16 }$

${ \longrightarrow 2 - 1c = 5c - 16 }$

${ \longrightarrow 2 + 16 = 5c + 1c }$

${ \longrightarrow 18 = 6c }$

Dividing both sides by 6

${ \longrightarrow 3 = c }$

Hence c = 3.

8 0

3 years ago

Please help! Look at the picture.

monitta

Answer:

Step-by-step explanation:

(27)^(-1/3) + (32)^(-2/5)

1/3 + 1/4

4/12 + 3/12 = 7/12

8 0

3 years ago

The value of blank divided 40.01 is much less than one?

patriot [66]

Answer:400

Step-by-step explanation: im coo like that

6 0

2 years ago

Read 2 more answers

PLZ HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

nika2105 [10]

2. A
4. D
I don't know the rest but good luck.

4 0

3 years ago

Establish for which constants c the following function is a density.

Valentin [98]

By "density" I assume you mean "probability density function". For this to be the case for $f(x)$ , we require

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=1$

Since

$f(x)=\begin{cases}cx^{1/2}&\text{for }0$

you have

$\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1$

which means

$c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}$

7 0

3 years ago