The equation of the sphere centered at 0, and radius 4 is:
,
note that this equation describes exactly the points of the surface of the square. That is, this is an EMPTY sphere.
The solid sphere, that is the points on the surface and all points in the inside, are given by :
since we want the left part of the solid part, picture 2, we add the condition x<0,
thus "the solid left (x < 0 is left) hemisphere of a sphere of radius 4 centered at the origin" is given by the system of inequalities:
Answer: 90 yards
Step-by-step explanation:
10 by 3 by 3 is 90
Answer:
We know that the equation of the circle in standard form is equal to <em>(x-h)² + (y-k)² = r²</em> where (h,k) is the center of the circle and r is the radius of the circle.
We have x² + y² + 8x + 22y + 37 = 0, let's get to the standard form :
1 - We first group terms with the same variable :
(x²+8x) + (y²+22y) + 37 = 0
2 - We then move the constant to the opposite side of the equation (don't forget to change the sign !)
(x²+8x) + (y²+22y) = - 37
3 - Do you recall the quadratic identities ? (a+b)² = a² + 2ab + b². Now that's what we are trying to find. We call this process <u><em>"completing the square"</em></u>.
x²+8x = (x²+8x + 4²) - 4² = (x+4)² - 4²
y²+22y = (y²+22y+11²)-11² = (y+11)²-11²
4 - We plug the new values inside our equation :
(x+4)² - 4² + (y+22)² - 11² = -37
(x+4)² + (y+22)² = -37+4²+11²
(x+4)²+(y+22)² = 100
5 - We re-write in standard form :
(x-(-4)²)² + (y - (-22))² = 10²
And now it is easy to identify h and k, h = -4 and k = - 22 and the radius r equal 10. You can now complete the sentence :)
Answer:
x = 7.9
Step-by-step explanation:
Given:
Angle - 44
Hypotenuse - 11 ft
adjacent side - x
having adjacent and hypotenuse use Cosine to solve the problem from
S-oh C-ah T-oa
cos (angle) = adjacent / hypotenuse
**Make sure your calculator is in degree mode**
cos 44 = x/11
if you cross multiply, you get
11 cos 44 = x
or to solve for x you would multiply both sides by 11 and get
11 cos 44 = x
x = 7.9
If K is midpoint of JL then JK = 0.5JL
JL = 4x - 2; JK = 7
The equation:
0.5(4x - 2) = 7
2x - 1 = 7 |add 1 to both sides
2x = 8 |divide both sides by 2
<u>x = 4</u>
<u>JL</u> = 4(4) - 2 = 16 - 2 = <u>14</u>
<u>KL</u> = JK =<u> 7</u>
