X / 6/7 is 3 2/5. First, concert the numbers to decimals for simplicity sake, and you get x/.857 = 3.4. Multiply both sides by .857 to get x alone and you get x ≈ 2.9143
Answer:
25 y 3−15 y 2−10 y ... 25y3 - 15y2 - 10y = 5y • (5y2 - 3y - 2) ... 5y • (y-1) Add up the last 2 terms, pulling out common factors : 2 • (y-1
Answer:
No, he does not have enough
Step-by-step explanation:
To decorate each cupcake, Henry needs 3 walnuts. Each package has 27 walnuts. With each cupcake needing 3 walnuts, Henry can decorate 9 cupcakes in one package. He has 5 packages which means he can decorate 9*5=45 cupcakes. However, he is making 4 dozens which is 4*12=48. He will not have enough.
<h3>Given</h3>
A regular polygon with area 500 ft² and apothem 10 ft
Cost of fence is $7.95 per ft
<h3>Find</h3>
Part III The cost of fence around an area scaled to 60 times the size
<h3>Solution</h3>
You don't want to think too much about this, because if you do, you find the regular polygon has 3.087 sides. The closest approximation, an equilateral triangle, will have an area of 519.6 ft² for an apothem of 10 ft.
For similar shapes of scale factor "s", the larger shape will have an area of s² times that of the smaller one. Here, it appears the area scale factor s² is 60, so the linear scale factor is
... s² = 60
... s = √60 ≈ 7.7460
The perimeter fence of the 500 ft² area is presumed to be 100 ft long (twice the area of the polygon divided by the apothem—found in Part I), so the perimeter fence of the industrial farm is ...
... (100 ft)×7.7460 = 774.60 ft
and the cost to construct it is
... ($7.95/ft)×(774.60 ft) ≈ $6158
