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Ksju [112]
2 years ago
8

Find the slope of the line that passes through each pair of points. Expressed as a fraction in simplest form. (8,2),(8,-1)

Mathematics
1 answer:
boyakko [2]2 years ago
8 0

Answer:

x = 8

Step-by-step explanation:

The explanation are the pictures. I hope I gave you the correct answer.

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Please solve thank you ​
Y_Kistochka [10]

9514 1404 393

Answer:

  2

Step-by-step explanation:

The second step of the solution shows division by 2 on the left. Consequently, it must also show division by 2 on the right.

  2 goes in the green box

_____

  \dfrac{2p}{2}=\dfrac{18}{2}\\\\p=9

7 0
3 years ago
A day care facility is open six days a week. The numbers of children who
Igoryamba

Answer:

23

Step-by-step explanation:

23 is the only number that is told the  MOST not least let me know if you need any more help ---shadow5555

5 0
3 years ago
How do you graph the function f(x)=−1/4x−2?
Georgia [21]
Welll the y-intercept is negative 2 so on the y axis the first point is negative 2. 1/4 is the rise over run so you would go up from your first point one unit and over to the left four units or vise versa down one unit and over to the right four units, or the image

4 0
4 years ago
The legs of a right triangle are 5 and 7 cm long, respectively. What is the length of the hypotenuse? If necessary, round your a
valentinak56 [21]
A squared plus B squared equals C squared, so what you need to do it square 5 and 7. 5 = 25 7 = 48 Then add then and square root your answer. 48 + 25 = 73. 73 square rooted equals an rounded amount of 8.6. SO the answer is D
4 0
3 years ago
How does the value of log Subscript 2 Baseline 100 compare with the value of Log Subscript 6 Baseline 20?
SCORPION-xisa [38]

Answer:

  • The value of   \log_2 100   is about 4 times the value of    \log_6 20

Explanation:

<u>1. Change of base rule</u>

       \log_ab=\dfrac{\log_{10}b}{\log_{10}a}=\dfrac{\log b}{\log a}

<u>2. Apply change of base rule to each of the given logarithm</u>

       \log_2 100=\dfrac{\log 100}{\log 2}\approx 6.64

       \log_6 20=\dfrac{\log 20}{\log 6}\approx 1.67

<u>3.Compare</u>

          \dfrac{6.64}{1.67}\approx 3.97\approx 4

<u>4. Conclusion</u>

The value   \log_2 100   is about 4 times the value of   \log_6 20

3 0
3 years ago
Read 2 more answers
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