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sleet_krkn [62]
3 years ago
11

Does the graph represent a function? just a lil help for khan academy students

Mathematics
1 answer:
cupoosta [38]3 years ago
4 0

Yeah also you got it correct, congrats.

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Enter an inequality that represents the graph in the box.
ANTONII [103]

The inequality that represents the graph in the box  is

y>-3x+6

Given :

The graph of the linear inequality

Lets pick two points from the graph to frame the linear equation

Slope intercept form of the equation is

y=mx+b

Where m is the slope and b is the y intercept

y intercept is (0,6) from the graph

so b=6

Now we find out slope m  using formula

Pick two points (0,6) and (2,0)

slope = \frac{y_2-y_1}{x_2-x_1} \\m=\frac{0-6}{2-0} =-3

m=-3

So the equation is y=-3x+6

Now we check the inequality sign by testing any point on shaded area

lets pick (4,0)

lets plug in 4 for x  and 0 for y

y=-3x+6\\0=-3(4)+6\\\\0=-6\\0>-6

The inequality for the given graph is

y>-3x+6

we cannot use >= sign because we have dotted lines

Learn more : brainly.com/question/17203372

5 0
3 years ago
State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
Please help
Drupady [299]

Answer:

56°

Step-by-step explanation:

2x+3x+5=90

5x=90-5

5x=85

x=85÷5

x=17

m<2=3x+5=3(17)+5=51+5=56

3 0
3 years ago
Help i need help please
solong [7]

Answer:

hope it is correct

Step-by-step explanation:

i think it is more than, can , cannot, and required

7 0
3 years ago
Dimensions of Box 2:x by 4x-1 by x^3 <br> The volume of Box 2 is given by
PIT_PIT [208]

Answer:

4x^5 – x^4

Step-by-step explanation:

i took it and was correct

6 0
3 years ago
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