Yes because that is what it is because that is the answer
Answer:
![\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2y%5E3%7D%2B2%5Csqrt%7Bx%5E3y%5E4%7D%2Bxy%5Csqrt%7By%7D%3D2xy%5E2%5Csqrt%7Bx%7D%2B2xy%5Csqrt%7By%7D)
Hence, ption B is true.
Step-by-step explanation:
Given the expression
![\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2y%5E3%7D%2B2%5Csqrt%7Bx%5E3y%5E4%7D%2Bxy%5Csqrt%7By%7D)
solving the expression
![\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2y%5E3%7D%2B2%5Csqrt%7Bx%5E3y%5E4%7D%2Bxy%5Csqrt%7By%7D)
as
![\sqrt{x^2y^3}=xy\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2y%5E3%7D%3Dxy%5Csqrt%7By%7D)
![2\sqrt{x^3y^4}=2xy^2\sqrt{x}](https://tex.z-dn.net/?f=2%5Csqrt%7Bx%5E3y%5E4%7D%3D2xy%5E2%5Csqrt%7Bx%7D)
so the expression becomes
![\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}](https://tex.z-dn.net/?f=%5C%3A%5Csqrt%7Bx%5E2y%5E3%7D%2B2%5Csqrt%7Bx%5E3y%5E4%7D%2Bxy%5Csqrt%7By%7D%3Dxy%5Csqrt%7By%7D%2B2xy%5E2%5Csqrt%7Bx%7D%2Bxy%5Csqrt%7By%7D)
Group like terms
![=2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}](https://tex.z-dn.net/?f=%3D2xy%5E2%5Csqrt%7Bx%7D%2Bxy%5Csqrt%7By%7D%2Bxy%5Csqrt%7By%7D)
Add similar elements
![=2xy^2\sqrt{x}+2xy\sqrt{y}](https://tex.z-dn.net/?f=%3D2xy%5E2%5Csqrt%7Bx%7D%2B2xy%5Csqrt%7By%7D)
Therefore, we conclude that:
![\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}](https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2y%5E3%7D%2B2%5Csqrt%7Bx%5E3y%5E4%7D%2Bxy%5Csqrt%7By%7D%3D2xy%5E2%5Csqrt%7Bx%7D%2B2xy%5Csqrt%7By%7D)
Hence, option B is true.
Answer:
He should expect to select 75 yellow cards.
Step-by-step explanation:
Since there is replacement, for each trial, we have:
1 yellow card
1 red card
1 blue card
1 green card.
If Greg does this 300 times, how many yellow cards should he expect to select?
Each trial, there are 4 cards, one of which is yellow. So 1/4 = 0.25 probability of selecting a yellow card.
Over 300 trials
0.25*300 = 75
He should expect to select 75 yellow cards.
Answer:
$24.11
Step-by-step explanation:
Let the cost of the present be c.
Then (3/4)c = $18.33.
To isolate (solve for) c, mult. both sides of this equation by (4/3):
(4/3)(3/4)c = (4/3)($18.33), or
c = $24.11
Answer:
A=10506.25 Sq.yards
Step-by-step explanation:
Width of the park=85 yds
Lenght of the park=120 yds
Now,
A=L*W
A=120*85
A=10200 square yards. This is the area of your given rectangle.
Now,
P=2(L+W)
P=2(120+85)
P=2(205)
P=410 this is the perimeter of your given rectangle.
Now,
a=410/4=102.5
Now,calculate the area of newly given distance of each side:
A=a^2
A=102.5^2
A=10506.25 Sq. Yards
This is the new area and is larger than the area of the given rectangle which was 10200 square yards.