(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°
(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°
Solution:
(1) In the given image ABC and DBE are vertical angles.
<u>Vertical angle theorem:</u>
If two angles are vertical then they are congruent.
⇒ ∠ABC = ∠DBE
⇒ 3x° + 38° = 5x° + 20°
Arrange like terms one side.
⇒ 38° – 20° = 5x° – 3x°
⇒ 18° = 2x°
⇒ x° = 9°
∠ABC = 3(9°) + 38° = 65°
∠DBE = 5(9°) + 20° = 65°
Adjacent angles in a straight line = 180°
⇒ ∠ABC + ∠CBE = 180°
⇒ 65° + ∠CBE = 180°
⇒ ∠CBE = 115°
∠ABD and ∠CBE are vertical angles.
∠ABD = 115°
(2) In the given image ABC and DBE are vertical angles.
⇒ ∠ABC = ∠DBE
⇒ 4x° + 2° = 5x° – 13°
Arrange like terms one side.
⇒ 13° + 2° = 5x° – 4x°
⇒ 15° = x°
∠ABC = (4(15°) + 2°) = 62°
∠DBE = 5(15°) – 13° = 62°
Adjacent angles in a straight line = 180°
⇒ ∠ABC + ∠CBE = 180°
⇒ 62° + ∠CBE = 180°
⇒ ∠CBE = 118°
∠ABD and ∠CBE are vertical angles.
∠ABD = 118°
Answer:
45 degrees
Step-by-step explanation:
Its ez
Answer:
28 degrees
Step-by-step explanation:
Because a triangle equals 180, you can subtract 90 and 34 from triangle ABE to leave you with 56 degrees for angle B.
Since CBA is a straigth line with 180 degrees, you can subtract 56 to end up with 124 degrees for angle CBE.
Since line BD bisects angle EBC (splits in half), you can divide the 124 degrees into 62 degrees.
Now that we know angle CBE equals 62 degrees, we can add the 90 degrees and subtract them from the 180 degrees of the triangle.
62+90=152
180-152=28
29.99x-8.75x=17884
21.24x=17884
X=841 sunglasses
It actually comes out to be more than 841, but since you can’t make .9 sunglasses then you round to the lower whole number.
