What quadratic equation has roots 7 and -2/3
1 answer:
Answer:
(x-7)(x+2/3)
Step-by-step explanation:
To easily find an equation with said roots, use the intercept form:
y=a(x-p)(x-q), where p and q are your roots.
y=(x-7)(x-(-2/3) = y=(x-7)(x+2/3)
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