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belka [17]
3 years ago
5

What quadratic equation has roots 7 and -2/3

Mathematics
1 answer:
-BARSIC- [3]3 years ago
6 0

Answer:

(x-7)(x+2/3)

Step-by-step explanation:

To easily find an equation with said roots, use the intercept form:

y=a(x-p)(x-q), where p and q are your roots.

y=(x-7)(x-(-2/3) = y=(x-7)(x+2/3)

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Bonnie's orange was cut into eights. she ate 3/8 of the orange and her friend ate 3/8 of it. Did they eat the whole orange? expl
Georgia [21]
No they did not eat the whole thing. They are 6 out of 8 pieces of the orange. Therefore there is still 2 pieces left
5 0
3 years ago
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Which is traveling faster, a car whose velocity vector is 201 + 25), or a car whose velocity vector is 30i, assuming that the un
Snowcat [4.5K]

Answer:

2nd car is running faster than the first car by 2.01 units.

Step-by-step explanation:

Let's assume that

  • the velocity of first car,

v_1\ =\ 20i\ +\ 25j

  • and the velocity of second car

v_2\ =\ 30i

=> speed of first car,

u_1\ =\ \sqrt{(20)^2+(25)^2}

      =\ \sqrt{400+625}

       =\ \sqrt{1025}

       = 32.01 units

and speed of second car,

u_2\ =\ \sqrt{(30)^2+(0)^2}

        = 30 units

u_2\ -\ u_1\ =\ 32.01\ -30

               = 2.01 units

Hence, 2nd car is running faster than the first car by 2.01 units.

8 0
3 years ago
Kristen and melissa spent 35% of their $32 on movie tickets. how much money did they spend
Ostrovityanka [42]

Answer:

11.2$

Step-by-step explanation:

Kristina and Melissa had 32$ at total

● 32$ => 100%

They have spent 35%

Let x be that amount

● x => 35%

●32 => 100

● x => 35

● x = (35×32)/100 = 11.2$

They have spent 11.2$

3 0
3 years ago
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Consider a single spin on the spinner shown below. A circle is split into sections 1, 2, 4, and 3. A spinner is pointing at numb
vladimir2022 [97]

Answer:

The answer is "Options A, B, and E represent mutually exclusive events".

Step-by-step explanation:

Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.

In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.

In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.

In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.

In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.

In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.

3 0
3 years ago
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For some reason, i forgot how to do this question... could someone help me?
AnnZ [28]
\frac{3}{5} :11=  \frac{3}{5} : \frac{11}{1} = \frac{3}{5} * \frac{1}{11} = \frac{3}{55}
3 0
3 years ago
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