3 years ago

What quadratic equation has roots 7 and -2/3

Mathematics

1 answer:

-BARSIC- [3]3 years ago

6 0

Answer:

(x-7)(x+2/3)

Step-by-step explanation:

To easily find an equation with said roots, use the intercept form:

y=a(x-p)(x-q), where p and q are your roots.

y=(x-7)(x-(-2/3) = y=(x-7)(x+2/3)

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