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3 years ago

5

What quadratic equation has roots 7 and -2/3

1 answer:

-BARSIC- [3]3 years ago

6 0

Answer:

(x-7)(x+2/3)

Step-by-step explanation:

To easily find an equation with said roots, use the intercept form:

y=a(x-p)(x-q), where p and q are your roots.

y=(x-7)(x-(-2/3) = y=(x-7)(x+2/3)

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Hello Love!! ♡　

»»————- $\red{Answer\:}$ ————-««

$\Huge{\boxed{\frac{1}{4}}}$

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Lapatulllka [165]

<u>Answer:</u>

g (h (x) ) = 5/8

<u>Step-by-step explanation:</u>

We are given the following two functions and we are to find the value of $g ( h ( - 3 ) )$ :

$g ( x ) = \frac { x + 1 } { x + 2 }$

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Firstly, we need to find the function :

$g ( h ( x ) ) = \frac { ( 4 - x + 1 ) } { ( 4 - x - 2 ) } = \frac { 5 - x } { 2 - x }$

Now substituting the value $x=-3$ in it:

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2 years ago