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Damm [24]
3 years ago
8

Simplify: (6 + 2iX6 - 21)

Mathematics
2 answers:
snow_tiger [21]3 years ago
7 0

If simplify it would be -15 + 12i

Anarel [89]3 years ago
3 0

Answer:

If the X in the middle is shown as multiplication, then the answer is -15 + 12i

EQUATION: (6 + 2iX6 - 21)

STEP 1:

SPLIT UP THE COMMON FACTORS

<h2> a. 6 - 21 </h2><h2> b. (2i X 6)</h2>

STEP 2:

SOLVE AS SHOWN

<h2> a. 6 - 21 = -15 </h2><h2> b. 12i</h2>

STEP 3:

ADD EVERYTHING TOGETHER

<h2>= -15 + 12i</h2>

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The ordered pair (1,0) is a solution to the inequality y
Sveta_85 [38]

Answer:

can u please be more specific i don't rlly understand.

7 0
4 years ago
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If f(1)=6 and f(n)=f(n-1)+2 then find the value of f(4).
Brilliant_brown [7]
The answer would be to subtract
4 0
3 years ago
A farmer with 1000 feet of fencing wants to enclose a rectangular field and then divide it into two plots with a fence parallel
Kipish [7]

Answer:

41,666.67m2

Step-by-step explanation:

Call W the Width and L the Length with 3 pieces.

The total length will be 2W + 3L

The Area is L*W

so,

A = L*W

2W+3L = 1000

Solve for L

3L = 1000-2W

L = (1000-2W)/3

subtitute for L into the first equation

A = L*W

A = W*(1000-2W)/3

A = (1000W - 2W^2)/3

Now, to find the max, set the 1st derivative = 0. I don't know if you know what that means, but...

dA/dW = 1000/3 - 4W/3 = 0

1000 - 4W = 0

W = 250 meters

Solve for L

2W+3L = 1000

500 + 3L = 1000

3L = 500

L = 166.67 m

Area = 250*500/3 = 41,666.67m2.

8 0
3 years ago
ladder 5m tall when set against a wall of house just reach the window at a height 3m how far is the lower end of ladder from the
KATRIN_1 [288]

Answer:

4

Step-by-step explanation:

A simple matter of using Pythagoras. The hypotenuse is the ladder, and one of the legs is the wall, and we have to figure out the value of the other leg.

The Pythagorean formuda is (hypotenuse = a): a² + b² = c² (b and c are the other sides)

applying the values: a = 5 and b or c is 3 (I'll put b = 3)

5² = 3² + c²

25 = 9 + c²

25 - 9 = c²

16 = c²

√16 = c

4 = c

c = 4

3 0
3 years ago
Please help me understand this problem! I don’t understand the methods to understand how to solve it
Doss [256]

Answer:

Perimeter at the big rectangle is 156 cm.

Step-by-step explanation:

Let's see how to calculate it.

1. First of all you know that perimeter in the blue one is 20cm, so imagine this:

L (long side); S (short side)

2L + 2S =20

and we consider that L = 4S

So, solving the equation:

2.4S + 2S =20

10S=20

S=20/10

S=2

L=8

2. Side at the gold square is 8, the same at the long side in the blue rectangle. So, if you see on the right side in the big one, we got 2 + 8 + 8 + (?). Take a look to the green. Green square is the gold + a short piece and you can understand the short piece as 2 short sides from the blue. If we give numbers we have 8 + 2 + 2, 12.

Now, 2+8+8+12 = 30cm

3. Let's go to the long side in the big one.

We have long side from blue (8) and as you see, side at the orange square must be side at the yellow + short at the blue, so 8+2 =10. We have four oranges square so 10+10+10+10=40, and +8 =48

4. Now that we have the two sides in the big one, let's find the perimeter with the rectangle formula:

2L + 2S =P

2.48 + 2.30 = 156 cm.

7 0
3 years ago
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