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kvv77 [185]
2 years ago
9

On the first day after arriving in Miami for spring break vacation, Matt plays out in the sun for six hours. Later that night he

notices that the skin on his legs and arms becomes red, swollen and extremely painful. By morning all of the afflicted areas have developed numerous blisters. These areas cover about 30% of his trunk (front and back) and 40% of the arms and legs.What organ has been damaged? What general types of tissue have been afflicted?What type of burn has Matt received? Explain.List ALL layers of the skin that have been damaged.What tissue repair process causes the blistering?List all of the body functions that may be disrupted by such a burn.After a few days his skin peels and the burned areas begin to heal. Matt notices that the healing areas are more susceptible to injuries due to chafing or trauma. During the next week after Matt returns to Tampa, Maria tells him that a sunburn prepares his skin for a deep tan. Maria encourages him to quickly begin tanning sessions at a local tanning salon before the effects of the burn wear off.What has happened to the skin that would cause this increased susceptibility?What would you advise him to do? Why?Is a deep tan a sign of skin that is healthy or severely stressed? Explain.
Biology
1 answer:
galina1969 [7]2 years ago
5 0

Answer:

Miami is is kanada

Explanation:

its c

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The only thing that can scratch Corundum is diamond.

Explanation:

We refer to the Mohs Hardness Scale for the hardness levels. We can see that Corundum is a level 9 which is the second highest so at a level 10 we see diamond, therefore diamond is the only thing that can scratch Corundum.

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Three different alleles (c1, c2, and c3) at the c locus exist in a hypothetical population of juniper trees. If the frequency of
prisoha [69]

Answer:

d

Explanation:

When considering the frequency of the potential alleles of a gene in a population, the total must add up to 1. Think of it like percentages. an allele frequency of 0.3 means 30% of the population carry it (out of a possible 100%).

We know that the frequency of c1 is 0.3. Lets take each option and see if it can be true

a) cannot be less than 0.3.  - false. It <em>could </em>be less than 0.3. For example, it could be 0.1, meaning the frequency of allele c3 would be 0.6 (because 0.3 + 0.1 + 0.6 = 1)

b) cannot be greater than 0.3. - false. It <em>could </em>be greater than 0.3. For example, it could be 0.5, meaning the frequency of allele c3 would have to be 0.2 (because 0.3 + 0.5 + 0.2 = 1)

c) is 0.7.  - false. It <em>can't </em>be 0.7, because that would mean that the frequency of c3 is 0. (0.7 + 0.3 = 1)

d) cannot be greater than 0.7. - true. It <em>cannot </em>be greater than 0.7, because  that would mean that the frequency of c3 is 0. (0.7 + 0.3 = 1)

5 0
3 years ago
Suppose the frameshift mutation was still present, but now there was a base substitution (A to C) in the arginine (R) codon, cha
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Answer:

A. The rest is still out of frame

Explanation:

The mRNA codon translated to amino acids is placed below.

While serine, which is one of the amino acids in the original protein, is still there as a part of the new sequence, there are a host of other frame shift mutations. While it is possible to phosphorylate a serine in any of these amino acid sequences, the secondary and tertiary structure of these are different to each other.

Original:

5' - UG | GUC | GGC | GAG | AAC | GAA | AGC | GC - 3'  

              Val     Gly      Glu      Asn     Glu      Ser

Mutation:

5' - UG | GUC | GGG | AGC | ACG | AAA | GCG | C - 3'

              Val      Gly      Ser      Thr     Lys      Ala      

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