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Y_Kistochka [10]
3 years ago
11

A certificate of deposit whith principal $150 earns 4%annual interest for 2 years

Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

$162 ( or 162.24 when interest compounded)

Step-by-step explanation:

If 4% is simple interest, $150 after 2 years

150 x (1 + 0.04 x 2) = 150 x 1.08 = 162.00

If it is compound interest

150 x (1 + 0.04)² = 150 x 1.0816 = 162.24

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At a restaurant, your bill has a food total of $45.50. Find the amount of an 18% tip on the food total.
oksano4ka [1.4K]
$53.69

45.50+8.19 (45.50 times 18%)=$53.69
8 0
3 years ago
Read 2 more answers
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sergiy2304 [10]

C. x³-4x²-16x+24.

In order to solve this problem we have to use the product of the polynomials where  each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.

Multiply the polynomials (x-6)(x²+2x-4)

Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:

(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)

x³+2x²-4x -6x²-12x+24

Ordering the similar monomials:

x³+(2x²-6x²)+(-4x - 12x)+24

Getting as result:

x³-4x²-16x+24

3 0
3 years ago
If you bought a stock last year for a price of $103, and it has risen 7% since then, how
Marrrta [24]

Answer:

the stock is worth $110.21

Step-by-step explanation:

The first thing you want to do is multiply 0.07 and 103, to find out what 7% of 103 is. When you multiply those two numbers you are going to get 7.21. You are then going to add 103 and 7.21 to find out how much it would be worth now.

7 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
const2013 [10]

Answer:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.

This means that n = 1067, \pi = \frac{74}{1067} = 0.069

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).

7 0
2 years ago
What is the domain of the function given below
MA_775_DIABLO [31]

Answer:

c. [-1, infinity)

Step-by-step explanation:

the domain the interval or set of valid x values (while the range is the same for the valid y values).

what is the smallest value of x we see for the graph ?

for x values we need to look left and right.

and the more left the value, the smaller it is.

so, in other words, what is the left-most x value e can find ?

x = -1

that is the "starting point" of the function. there is no functional value for any smaller x.

and then clearly, the function goes on and on to the right without any boundary in sight. so, it keeps going to the right in all eternity, that means it goes to infinity.

therefore the answer.

keep in mind that "infinity" is not a number, only a concept. so, when writing "infinity" at an interval end, it is not included (and we use a round bracket).

8 0
2 years ago
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