The answer is 2^27 because the 2 is supposed to stay the same and 9*3=27.
Hope this helped☺☺
The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-400--800)2+(300-200)2
d = √ ((400)2+(100)2)
d = √ (160000+10000)
d = √ 170000
The distance between the points is 412.310562561766
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(-800+-400)/2=-600
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(200+300)/2=250
The midpoint is: (-600,250)
Graphing the two points, midpoint and distance
P1 (-800,200)
P2 (-400,300)
Midpoint (-600,250)
The length of the black line is the distance between the points (412.310562561766)
It would cost $896 to plate fencing around the garden
Let us bear in mind the equivalent value of these coins:
One dime = $0.10
One quarter = $0.25
Let x = number of dimes
y<span> = number of quarters</span>
Since the boy has 70 coins in total, we can say that:
<span>x + y = </span><span>70 </span>(can be written as x = 70 – y)
Since the boy has a total of $12.40, we can say that:
0.10x + 0.25y = 12.40
To solve this problem, we need to solve this system of equation. We have to substitute the value of x as written in the first equation (x = 70 –y)
0.10(70 – y) + 0.25y = 12.40
7 – 0.10y + 0.25y = 12.40
0.15y = 5.40
y = 36
X = 70 – 36
X = 34
Therefore,<span> the boys </span>has<span> 34 dimes and 36 quarters. To check our answer, we just have to check if his money would total $12.40.</span>
34 dimes = $3.40
36 dimes = $9.00
<span>Total </span><span>$12.40</span>
