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pav-90 [236]
2 years ago
13

In triangle RST, SQ=8 and QT=12. Find SW and UQ

Mathematics
1 answer:
Doss [256]2 years ago
6 0

Given:

In triangle RST, SQ=8 and QT=12.

To find:

The measure of sides SW and UQ.

Solution:

We know that centroid of a triangle is the intersection point of the medians and it divides each median in 2:1.

In the given figure SW and TU are medians and Q is the centroid. So,

\dfrac{SQ}{QW}=\dfrac{2}{1}

\dfrac{8}{QW}=\dfrac{2}{1}

\dfrac{8}{2}=QW

4=QW

Now,

SW=SQ+QW

SW=8+4

SW=12

TU is a median. So,

\dfrac{QT}{UQ}=\dfrac{2}{1}

\dfrac{12}{UQ}=\dfrac{2}{1}

\dfrac{12}{2}=UQ

6=UQ

Therefore, the measure of SW is 12 units and the measure of UQ is 6 units.

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Which of the equations below could be the equation of this parabola?
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Answer:

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Step-by-step explanation:

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y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

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\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

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