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AleksandrR [38]
2 years ago
12

Find two consecutive whole numbers that square root 97 lies between

Mathematics
2 answers:
lora16 [44]2 years ago
8 0

Answer: 9 and 10

Step-by-step explanation:

To understand this question we need to first understand how to solve square root equations! The easiest way to learn how to solve square root problems is by finding the reverse of the problem.

For example, if you tried to find the square root of 25, you would reverse the problem to do 5^2 = 5 x 5 = 25.

So if we were to implement this problem, we would look at these two whole numbers.

9^2 = 9 x 9 = 81

10^2 = 10 x 10 = 100

Thus meaning that the only two numbers that the square root of 97 lies between can be 9 and 10!

It's important to rely on your knowledge of multiplication to develop a strong base for square roots.  

antoniya [11.8K]2 years ago
7 0

Answer:

9 & 10

Step-by-step explanation:

97 lies between two perfect squares, 81 and 100

Hence sqrt(97) would lie between sqrt(81) and sqrt(100), which are 9 and 10

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Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-5) and (x-6)
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The perimeter of a rectangular field is 60 meters. Its area is 200 square meters. Find its dimensions.
Vanyuwa [196]

Answer:

20 m by 10 m

Step-by-step explanation:

let w be width and l be length , then

2(l + w) = 60 ( divide both sides by 2 )

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l = 30 - w → (1)

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Substitute l = 30 - w into (2)

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1. If RU = 16, UT = 20, and SR = 16, what is the perimeter of SUT?
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Answer:

72

Step-by-step explanation:

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2 years ago
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