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3 years ago

Find two consecutive whole numbers that square root 97 lies between

Mathematics

2 answers:

lora16 [44]3 years ago

8 0

Answer: 9 and 10

Step-by-step explanation:

To understand this question we need to first understand how to solve square root equations! The easiest way to learn how to solve square root problems is by finding the reverse of the problem.

For example, if you tried to find the square root of 25, you would reverse the problem to do 5^2 = 5 x 5 = 25.

So if we were to implement this problem, we would look at these two whole numbers.

9^2 = 9 x 9 = 81

10^2 = 10 x 10 = 100

Thus meaning that the only two numbers that the square root of 97 lies between can be 9 and 10!

It's important to rely on your knowledge of multiplication to develop a strong base for square roots.

antoniya [11.8K]3 years ago

7 0

Answer:

9 & 10

Step-by-step explanation:

97 lies between two perfect squares, 81 and 100

Hence sqrt(97) would lie between sqrt(81) and sqrt(100), which are 9 and 10

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Use the following prompt to answer the next 6 questions. Suppose we want to test the color distribution claim on the M&M’s w

vitfil [10]

Answer:

The claim on the M&M’s website is not true.

Step-by-step explanation:

A Chi-square test for goodness of fit will be used in this case.

The hypothesis can be defined as:

H₀: The observed frequencies are same as the expected frequencies.

Hₐ: The observed frequencies are not same as the expected frequencies.

The test statistic is given as follows:

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}$

Here,

$O_{i}$ = Observed frequencies

$E_{i}=N\times p_{i}$ = Expected frequency.

The chi-square test statistic value is, 14.433.

The degrees of freedom is:

df = k - 1 = 6 - 1 = 5

Compute the p-value as follows:

$p-value=P(\chi^{2}_{k-1} >14.433) =P(\chi^{2}_{5} >14.433) =0.013$

*Use a Chi-square table.

The significance level is, α = 0.05.

p-value = 0.013 < α = 0.05.

So, the null hypothesis will be rejected at 5% significance level.

Thus, concluding that the claim on the M&M’s website is not true.

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3 years ago

Prove that: 16sin20.sin40.sin60.sin80=3

olga nikolaevna [1]

to prove that 6720. Sin 40. Sin 60. 80 equals 3 you'd have to divide 16 by 20 multiply subtract both sides by 3 which is 24x + 6x + 8x + -14 equals 40 40 + 20 equals 16 - -40 equals 80 which equals to 3

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4 years ago

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