A tessellation that uses only one type of regular polygon.
<h3>
What is Polygon?</h3>
The definition of a polygon is given as a closed two-dimensional figure with three or more straight lines.
When we cover a surface with a pattern of a flat geometric shapes such that there should have no overlaps or gaps, then the surface is called a tessellation.
A regular tessellation is tessellation made up by using only one type of regular polygon. These are made up of entirely congruent regular polygons all that joining vertex to vertex.
Hence, A is the correct option.
Learn more about Polygon from:
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Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.
{\text{Direction of parabola depends on the sign of quadratic coefficient of a }} \hfill \\
{\text{quadratic equation}}. \hfill \\
{\text{For given quadratic equation}}. \hfill \\
a{x^2} + bx + c = 0 \hfill \\
{\text{The parabola is in the upward direction if }}a{\text{ }} > {\text{ }}0{\text{ and in downward direction if }}a < 0 \hfill \\
{\text{Here, the equation of given parabola is }} \hfill \\
{x^2} - 6x + 8 = y \hfill \\
\Rightarrow y = \left( {{x^2} - 6x + 9} \right) - 9 + 8 \hfill \\
\Rightarrow y = {\left( {x - 3} \right)^2} - 1. \hfill \\
{\text{Thus, the parabola is in the upward direction}} \hfill \\
Answer: x ≥ 0
Step-by-step explanation:
First, let's define the symbols used:
a < x (this means that a is strictly smaller than x)
a > x (this means that a is strictly larger than x)
a ≤ x (this means that a is smaller than or equal to x)
a ≥ x (this means that a is larger than or equal to x)
Now we have the statement "x is no less than 0"
Then x can be equal to zero, or larger than zero, but never smaller than zero.
Looking at the symbols above, we know that we need to use:
x ≥ 0
(this is equivalent to the statement)
Can’t see your answer choices but the absolute value of -3 is 3 so I would say 3 is your answer
