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jasenka [17]
3 years ago
14

A rectangle has an area of 204.8 square inches and a height of 16 inches. What is the length of the base?

Mathematics
1 answer:
Vlada [557]3 years ago
3 0

The length of the base of the rectangle is 12.8 inches.

Here's an explanation:

The problem has stated that the area of the rectangle is 204.8 square inches, and that the height of the rectangle is 16 inches. The equation for finding the area of a rectangle is height *length = area. If you insert the values that we know, then the equation becomes 16*length = 204.8. We can alter the equation, and we can isolate the variable by dividing each side by 16. The equation then becomes length=204.8/16. 204.8/16 is equal to 12.8 inches, and that is the length of the rectangle.

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We can actually deduce here that the ordered pairs that make both inequalities true are:

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<h3>What is inequality?</h3>

An inequality is known to be an expression that shows that certain variables or values are not equal to each other. It is usually seen in an inequality expression as:

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We see the attached image that shows the graph of inequality and which completes the question.

The options that complete the question are:

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E. (2, 2)

When we insert the values of each axes into the inequality expressions given, we will discover that the ordered pairs that the inequalities true is (1,1) and (2, 2).

Learn more about inequality on brainly.com/question/25275758

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1 year ago
Suppose that A = PDP-1 . Prove that det(A) = det(D)
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Check.

Step-by-step explanation:

To prove it we need to know that  for two matrices A and B we have that:

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det(A) = det(P)*\frac{1}{det(P)}*det(D)

det(A) = det(D).

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