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givi [52]
2 years ago
10

Were using pythagorean theorem. Help if possible ​

Mathematics
2 answers:
jeyben [28]2 years ago
7 0

Answer:

1) 6

2) \sqrt{15}

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

Lena [83]2 years ago
5 0

Answer:

EF= 6 ft

ST= 3.8 yd

Step-by-step explanation:

c= \sqrt{a^2+b^2} \\

8^2+x^2=10^2

64+x= 100

-64  = -64

x= \sqrt{36}

x=6

EF= 6 ft

x^2+1^2=4^2

x+ 1= 16

 -1  = -1

x= \sqrt{15}

x= 3.8

ST= 3.8

Hope this helped :)

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miss Akunina [59]

2.56 is the value of the expression

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Use a Venn diagram to answer the question. A survey of 180 families showed that 67 had a​ dog; 52 had a​ cat; 22 had a dog and a
Mice21 [21]

Answer:

There are 13 families had a parakeet only

Step-by-step explanation:

* Lets explain the problem

- There are 180 families

- 67 families had a dog

- 52 families had a cat

- 22 families had a dog and a cat

- 70 had neither a cat nor a​ dog, and in addition did not have a​

 parakeet

- 4 had a​ cat, a​ dog, and a parakeet (4 is a part of 22 and 22 is a part

 of 67 and 520

* We will explain the Venn-diagram

- A rectangle represent the total of the families

- Three intersected circles:

 C represented the cat

 D represented the dog

 P represented the parakeet

- The common part of the three circle had 4 families

- The common part between the circle of the cat and the circle of the

 dog only had 22 - 4 = 18 families

- The common part between the circle of the dog and the circle of the

 parakeet only had a families

- The common part between the circle of the cat and the circle of the

 parakeet only had b families

- The non-intersected part of the circle of the dog had 67 - 22 - a =

  45 - a families

  had dogs only

- The non-intersected part of the circle of the cat had 52 - 22 - b =  

  30 - b families

  had cats only

- The non-intersected part of the circle of the parakeet had c families

  had parakeets only

- The part out side the circles and inside the triangle has 70 families

- Look to the attached graph for more under stand

∵ The total of the families is 180

∴ The sum of all steps above is 180

∴ 45 - a + 18 + 4 + 30 - b + b + c + a + 70 = 180 ⇒ simplify

- (-a) will cancel (a) and (-b) will cancel (b)

∴ (45 + 18 + 4 + 30 + 70) + (-a + a) + (-b + b) + c = 180

∴ 167 + c = 180 ⇒ subtract 167 from both sides

∴ c = 180 - 167 = 13 families

* There are 13 families had a parakeet only

5 0
3 years ago
I need help with the top 3 plz
attashe74 [19]

Answer/Step-by-step explanation:

Recall: SOHCAHTOA

1. Reference angle = 70°

Adjacent side = x

Hypotenuse = 6 cm

Apply CAH. Thus,

Cos 70 = adj/hyp

Cos 70 = x/6

6 × cos 70 = x

2.05 = x

x = 2.05 cm

2. Reference angle = 45°

Adjacent side = x

Hypotenuse = 1.3 m

Applying CAH, we would have the following ratio:

Cos 45 = adj/hyp

Cos 45 = x/1.3

1.3 × cos 45 = x

0.92 = x

x = 0.92 m

3. The who diagram is not shown well. Some parts are missing, however you can still solve the problem just the same way we solved problem 1 and 2.

6 0
3 years ago
Help plz<br>6(2x - 11) + 15 = 3x + 12​
Ket [755]

Answer:

x = 7

Step-by-step explanation:

Lets do the brackets first,

6 × 2x = 12

6 × -11 = -66

------

Calculate the x constant:

12x - 3x = 9x

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Then the ones with no x:

-66 + 15 = -51

51 + 12 = 63

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Lastly, divide

63 ÷ 9 = 7

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Have a good day :)

3 0
2 years ago
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