-2 1/2 / 6 would be -5/12, just turn - 2 1/2 into a decimal and divide by 6 :)
Answer:
A few examples:
VE: Three more than two times the temperature.
AE: 2x+3
VE: The money I have decreased by two thirds of the money you have.
AE: x - (2/3)y
VE: The number of friends I have increased by four times the amount of friends you have.
AE: x + 4y
Let me know if this helps!
Answer:
σ should be adjusted at 0.5.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean 12.
Assuming we can precisely adjust σ, what should we set σtobe so that the actual amount dispensed is between 11 and 13 ounces, 95% of the time?
13 should be 2 standard deviations above the mean of 12, and 11 should be two standard deviations below the mean.
So 1 should be worth two standard deviations. Then



σ should be adjusted at 0.5.
Use the PEMDAS method
-solve equation in parentheses
-solve exponents
-solve multiplication
-solve division
-solve addition then subtract
29. 5/2× 2/5×=5/2×7 multiply the equation by the reciprocal of the coefficient
x= 5/2×7/1 <span> reduce the numbers with 5,2. convert the expression into a fraction
</span><span>
x= 5</span>×7/2×1
<span>
x= 35/2
32. a= 19/6
2 3/4a = 19 1/4 divide both sides of the equation by 1/4
2</span>×3a=19 calculate the product <span>
</span>
6a=19 divide both sides by 6
a=19/6