It's 3.01 sorry wrong question please forgive me
A.51
because 5x15=75, 8x3=24, 75-24=51
Answer:
The coordinates of triangle A"B"C" will become
A( 5,-3 ) B( 9,6 ) C( -12 ,-4 )
Step-by-step explanation:
Original vertices of triangle ABC are ;
A ( -3, 5 ) B( 6, 9 ) C ( -4, -12 )
after reflection over x-axis
A( -3,-5 ) B( 6, -9 ) C( -4,12 )
when the triangle is rotated
x coordinates becomes -y while y coordinates becomes x
The coordinates of triangle A"B"C" will become
A( 5,-3 ) B( 9,6 ) C( -12 ,-4 )
Answer:
3 1/11
Step-by-step explanation:
8 1/2 x 4/11
Change to an improper fraction
(2*8+1)/2 * 4/11
17/2 * 4/11
68 /22
Divide the top and bottom by 2
34/11
Change back to a mixed number
11 goes into 34 3 times with 1 left over
3 1/11
<h2>
a. What is your equation?</h2>
This is a problem of projectile motion. A projectile is an object you throw with an initial velocity and whose trajectory is determined by the effect of gravitational acceleration. The general equation in this case is described as:

Where:

So:

Finally, the equation is:

<h2>b. How long will it take the rocket to reach its maximum height?</h2>
The rocket will reach the maximum height at the vertex of the parabola described by the equation
. Therefore, our goal is to find
at this point. In math, a parabola is described by the quadratic function:

So the x-coordinate of the vertex can be calculated as:

From our equation:

So:

So the rocket will take its maximum value after 1.99 seconds.
<h2>
c. What is the maximum height the rocket will reach?</h2>
From the previous solution, we know that after 1.99 seconds, the rocket will reach its maximum, so it is obvious that the maximum height is given by
. Thus, we can find this as follows:

So the maximum height the rocket will reach is 66.68ft
<h2>
d. How long is the rocket in the air?</h2>
The rocket is in the air until it hits the ground. This can be found setting
, so:

We can't have negative value of time, so the only correct option is
and rounding to the nearest hundredth we have definitively:
