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Molodets [167]
3 years ago
15

Item 5

Mathematics
1 answer:
miv72 [106K]3 years ago
5 0

Answer:

A. $41.40

Step-by-step explanation:

Take 36 multiply by the decimal percentage (.15) =5.4  then simply add

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Y-(5-(y-x)) x = 4 y = 6<br><br> I need the steps please, this is a little bit confusing..
KATRIN_1 [288]

Answer:

3

Step-by-step explanation:

substitute x = 4 , y = 6 into the expression

y - (5 - (x - y))

= 6 - (5 - (6 - 4))

= 6 - (5 - 2))

= 6 - 3

= 3

3 0
2 years ago
7. The length of a rectangle is 3 centimeters less than twice its width. The perimeter of the rectangle is 48 cm. What are the d
irga5000 [103]
The answer is b

The perimeter of a rectangle is 2(l + w) so in this case, it is 2(15 + 9) and that is equal to 48. But so at c and d. So u need to multiply the width by 2 (9*2=18) and then you’ll see that 18-3=15. And therefore, the length is -5 and the width is 9
5 0
3 years ago
Lydia graphed ΔDEF at the coordinates D (−2, −1), E (−2, 2), and F (0, 0). She thinks ΔDEF is a right triangle. Is Lydia's asser
alukav5142 [94]

Answer:

No; the slopes of segment EF and segment DF are not opposite reciprocals.

Step-by-step explanation:

The slope between two points O(e, f) and X (g,h) is given as:

slope\ of\ |OX|=\frac{h-f}{g-e}

The slopes of segment EF and segment DF are given below:

slope\ of\ |EF|=\frac{0-2}{0-(-2)}=-1\\\\slope\ of\ |DF|=\frac{0-(-2)}{0-(-1)}=2\\

For triangle DEF to be a right triangle, DF and EF are supposed to be perpendicular to each other. Two line are said to be perpendicular if the product of their slope is -1, i.e the slope of one line is the negative reciprocal (opposite reciprocal) of the other line.

Since the slope of DF and EF are not opposite reciprocals,  ΔDEF is not a right triangle.

3 0
3 years ago
En un taller de futbol se inscribieron en total 240 personas . de ese total 80% son mujeres . ¿Cuántos hombres se inscribieron e
horsena [70]
Answer: A
192 hombres
5 0
3 years ago
Can someone help me with this problem, please. The problem is attached.
timurjin [86]

y = 3 is the line of reflection

Under a reflection in a line, corresponding points of the original and it's image should be equidistant from the line of reflection

y = 3 is the horizontal line passing through all the points with a y-coordinate of 3

A is 1 unit above and A' is 1 unit below the line

B is 3 units above and B' is 3 units below

C is 1 unit below and C' is 1 unit above

D is 1 unit below and D' is 1 unit above

The vertices of the figure and the image are all equidistant from y = 3




3 0
3 years ago
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