Answer:
shouldn't there be a pictures with this Question
Step-by-step explanation:
Answer:
80,00![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,
![A = L*W](https://tex.z-dn.net/?f=A%20%3D%20L%2AW)
Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.
![A = 400ft*200ft](https://tex.z-dn.net/?f=A%20%3D%20400ft%2A200ft)
![A = 80,000ft^{2}](https://tex.z-dn.net/?f=A%20%3D%2080%2C000ft%5E%7B2%7D)
So the Maximum area we are able to create with 800 ft of fencing is 80,00![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
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The y intercepts are when x=0 (the line crosses the y axis) and the x intercepts are when y=0 (the line crosses the x axis). Plugging x=0 in, we get 5*0=2y+4. Subtracting 4 from both sides, we get -4=2y and by dividing both sides by 2 we get y=-2, for one intercept to be (0, -2). For the other intercept, we make y=0 to get 5x=2*0+4=4. Dividing both sides by 4, we get x=4/5, making our other intercept (4/5, 0)
Answer:
5
Step-by-step explanation:
ok thanks
Answer:
Undefined
Step-by-step explanation:
Formula: (14-6)/(0-0)
Simplify: 8/0
Which is undefined