Answer:
top = 17ft
bottom = -12ft
Step-by-step explanation:
As seen in the badly drawn picture attached in this question we are trying to find the point at the top of the ladder and the point at the bottom of the ladder. As seen in the picture ground level has an altitude of 0 ft meaning that lower than this would be in the negatives. Since the basement floor is 12 feet below ground level then this point would be -12 ft. Now since we know that the ladder is 29ft tall we simply add this height to the basement floor value to get the value of the 2nd floor ceiling (top of the ladder).
29ft + ( -12ft) = 17ft
Therefore we can see that the point at the top of the ladder is 17ft.
Answer:
The means is 8.5 The Median is 6
Step-by-step explanation:
1) to find the mean just Simply add all the numbers together and divided by how many numbers that is giving. (Because you are simply finding the average)
9+6+5+3+28+6+4+7=68
68 divided by 8 = 8.5
2) to find the median simply organize the numbers from least to greatest Like this: (3,4,5,6,6,7,9,28) Then keep crossing out from both sides teal you find the middle Number.
If there a odd amount of number the median will be one Number, if even 2 numbers ( if 2 numbers just add them both and divide by 2)
In This Case the Median is 6,6 but Its actually 6 Why (6+6=12) and (12/2=6) so your median is 6.
<em>Hopes This helps!</em>
Take 1/2 of -6 and square it
-6/2=-3
(-3)^2=9
9 should be added
x^2-6+9=5+9
(x-3)^2=14
9 should be added
4 spinach with $1.00 left over
The general solutions always have some additive/multiplicative constant, that you must fix in the particular solution.
In order to do so, you need to impose that the particular solution passes through a certain point. In your case, you have
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and you want
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Put everything together, and you have
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Since the cosine is zero in the chosen point. So, we've fixed the value of the constant, and the particular solution is found:
