Answer:
see consider there are three angle 80 and x and 45(the measure of line is 180 so subtract 180 by 125 u will get 45) now measure of angle is 180 soo the value of x is 55degree so value of x is equal to that of z therefore value of z also 55 degree
Answer: Scientific Notation is the expression of a number n in the form a∗10b. where a is an integer such that 1≤|a|<10. and b is an integer too. Multiplication: To multiply numbers in scientific notation, multiply the decimal numbers. Then add the exponents of the powers of 10.
Step-by-step explanation:
Answer:
27/50
Step-by-step explanation:
The equation which represents the people that want to visit the museum and the exhibit is 8n+5n.
As you can see, the variable n is present in both terms 8n and 5n of the equation, so we can now factor the equation. You create parenthesis in which you put inside 8+5 and then you throw the variable n outside the parenthesis, and you get at last:
8n + 5n = (8+5)n
Hope this helps! :D
To find the total area of this figure, it would be easiest to find the area of the left part (rectangle) and then find the area of the right part (triangle), and then add the two area values together.
First, we will find the area of the rectangle, using the formula A = lw, where l is the length of the rectangle and w is the width of the rectangle.
The length of the rectangle is 13 cm and the width is 9 cm. If we substitute in these values into our equation, we get:
A = (13cm)(9cm)
A= 117 cm^2
Next, let’s find the area of the triangle, using the formula A=(1/2)bh, where b is the base of the triangle and h is the height.
The base of the triangle is 11 cm and the height of the triangle is 5 cm (found by subtracting 13-8 as seen in the figure). If we substitute in these values and simplify, we get:
A=1/2(11cm)(5cm)
A=1/2(55cm^2)
A=27.5 cm^2.
When we add together the area of the rectangle with the area of the triangle, we will get the total area of the figure.
117 cm^2 + 27.5 cm^2 = 144.5 cm^2
Your answer is 144.5 cm^2 or the first option.
Hope this helps!
