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3 years ago

Find the area of the shape shown below. 4 4 8 2

Mathematics

2 answers:

dezoksy [38]3 years ago

5 0

Two shaped are merged so

One is square and the other is trapezoid so,

AREA OF SQUARE=4*4

=16

AREA OF TRAPEZOID=(2+4)x4/2

So,rhe answer will be

12+16=28

HOPE IT IS HELPFUL

Readme [11.4K]3 years ago

3 0

Answer: 28 units^2

Step-by-step explanation:

You basically have a square and a trapezoid merged together

4*4=16 for the square

(2+4)*4/2=12 for the trapezoid

12+16=28 is your answer

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17=5k-2 what Is (k) help me please

MAXImum [283]

17=5k-2
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3 years ago

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Slove algebraically 3x - 4y = -24 x +4y=8

Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

Solution:

We have been given two equations which are as follows:

3x - 4y = -24 ----- eqn 1

x + 4y = 8 -------- eqn 2

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

x = 8 - 4y ------eqn 3

Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

24 - 12y - 4y = -24

-16y = -48

y = 3

Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

x = 8 - 4(3)

x = 8 - 12 = -4

Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

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3 years ago

Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter. How long is the re

vekshin1

Answer:

$\frac{7}{10}$

Step-by-step explanation:

Carrie has 2 meters of ribbon. She cuts off pieces of ribbon that are 5/10 meter, 1/10 meter, and 7/10 meter

Lets add all the cut of pieces and subtract it from 2 meters

$\frac{5}{10} +\frac{1}{10}+\frac{7}{10}=\frac{13}{10}$

Now we subtract 13/10 from 2 meters

$2 - \frac{13}{10}$

To subtract , make the denominator same

$\frac{2*10}{1*10} - \frac{13}{10}=\frac{20}{10} - \frac{13}{10}=\frac{7}{10}$

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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