The dogs weight in kilograms is 13.5. Take the nine and divide it by 20, then multiply the 30 into that number.
Answer: No two students ran same distance
Step-by-step explanation:
Given
Stacy ran
of a km i.e.
![\Rightarrow 1\times \dfrac{9}{12}=\dfrac{3}{4}=0.75\ km](https://tex.z-dn.net/?f=%5CRightarrow%201%5Ctimes%20%5Cdfrac%7B9%7D%7B12%7D%3D%5Cdfrac%7B3%7D%7B4%7D%3D0.75%5C%20km)
Jules ran
of a km i.e.
![\Rightarrow 1\times \dfrac{4}{5}=0.8\ km](https://tex.z-dn.net/?f=%5CRightarrow%201%5Ctimes%20%5Cdfrac%7B4%7D%7B5%7D%3D0.8%5C%20km)
Raul ran
of mile i.e.
![\Rightarrow 1\times \dfrac{3}{4}=0.75\ miles\\\\\text{1 mile=1.6 km}\\\\\Rightarrow 0.75\ miles=1.2\ km](https://tex.z-dn.net/?f=%5CRightarrow%201%5Ctimes%20%5Cdfrac%7B3%7D%7B4%7D%3D0.75%5C%20miles%5C%5C%5C%5C%5Ctext%7B1%20mile%3D1.6%20km%7D%5C%5C%5C%5C%5CRightarrow%200.75%5C%20miles%3D1.2%5C%20km)
So, no two students ran the same distance.
Answer:
y ≥ 3x -1; x +3y ≤ 6
Step-by-step explanation:
Both lines are solid, so the only viable choices are those with "or equal to" in the comparison operators: the 2nd and 4th choices.
The line with a slope of +3 is shaded <u><em>above</em></u> the line, so that will correspond to the inequality ...
y ≥ 3x -1 . . . . . . . . . . found only in the 4th choice.