Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Sent a picture of the solution to the problem (s). I set it up as a proportion to solve.
your answer is C. plug in -1 for x and Y. 4(-1) + (-1). now add... -5. -5 is greater than -6 which is a ordered pair we needed to make this true
<h3>
Answer: 6 dollars per kilogram</h3>
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Explanation:
The mixed number 4 & 1/2 converts to the decimal form 4.5
The unit price is 27/(4.5) = 6 dollars per kilogram
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If you wanted, you can think of it like this ratio
4.5 kg : 27 dollars
Dividing both parts of that ratio by 4.5 will lead to
1 kg : 6 dollars
Answer:
n = 12
Step-by-step explanation:
84 / 7 = 12
May I have brainliest please? :)
