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Anika [276]
2 years ago
15

Todd has been helping his grandmother vanilla ice cream. Yesterday morning they made 4.5 quarts of ice cream. They are going to

store the ice
cream in pint sized containers to place in the freezer.
Calculate how many pint-sized containers Todd needs to store 4.5 quarts of ice cream.
Todd will need
pint-sized containers to store 4.5 quarts of ice cream
Mathematics
1 answer:
netineya [11]2 years ago
8 0

Answer:

Todd will need 9 pint-sized containers to store 4.5 quarts of ice cream.

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$0.20x + $1.25 = $10

Where x = ounces of salad

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Tell whether each set of events is independent or dependent (problems 1 - 4).
tatyana61 [14]

Answer:

1 dependent

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Step-by-step explanation:

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5 0
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A bicycle tire has a diameter of 62 \text{ cm}62 cm62, start text, space, c, m, end text. What is the distance the bicycle tire
navik [9.2K]

Answer:

The distance bicycle tire travels is <u>1946.8 cm</u>.

Step-by-step explanation:

Given:

Diameter of bicycle tire = 62 cm.

The bicycle tire travels in 10 revolutions.

Now, to find the distance the bicycle tire travels in 10 revolutions.

Diameter = 62 cm.

Radius (r) = \frac{Diameter}{2}=\frac{62}{2}=31\ cm.

So, we get the circumference first by putting formula:

Circumference =2\pi r

Circumference =2\times 3.14\times 31\\\\Circumference =194.68\ cm.

Thus, we get the <u><em>circumference of tire 194.68 cm.</em></u>

<u><em>Number of revolutions the tire travels = 10.</em></u>

Now, to get the distance the bicycle tire travels we multiply circumference of tire by number of revolutions the tire travels:

194.68\ cm\times 10\\\\=1946.8\ cm.

Therefore, the distance bicycle tire travels is 1946.8 cm.

4 0
3 years ago
Read 2 more answers
It took my question down twice here's a real math question I guess
aliina [53]

Answer:

n-3

Interval notation: (-\infty, -10)\cup(-3,\infty)

Step-by-step explanation:

<u>First inequality:</u>

<u />n+8

Therefore, this inequality restricts:

n \in \mathrm{R};\: n

<u>Second inequality:</u>

< 8+n-3

Therefore, this inequality restricts:

n \in \mathrm{R};\: n>-3

Therefore, with both of these restrictions together, we have:

\fbox{$n \in \mathrm{R}; n-3$}\\\mathrm{or\:}\fbox{$n-3$}\\\mathrm{or\:}\fbox{$(-\infty, -10)\cup(-3,\infty)$}.

4 0
3 years ago
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