PLEASE HELP ILL GIVE BRAINLIST. In ΔABC shown below, segment DE is parallel to segment AC:

The point V(4, –1) is rotated 90° clockwise around the origin. What are the coordinates of its image V’? V’(1, 4) V’(–1, 4) V’(–

tresset_1 [31]

Answer:

V' = (-1, -4)

Step-by-step explanation:

the original point V (4, -1) is 4 units to the right and 1 unit down.

now we turn this 90° clockwise (upper right to down to upper left).

that means the right part of the x-axis turns into the bottom part of the y-axis, and the bottom part of the y-axis into the left part of the x-axis.

so, positive x turns into negative y, and the negative y turns into negative x.

therefore, (4 -1) turns into (-1, -4).

7 0

2 years ago

Read 2 more answers

2. Consider the function, f(x)=x^3+x^2-9x-9

Sedaia [141]

The intercepts of the graph are:

x-axis interception: $\left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right)$ .

y-axis interception: $\left(0,\:-9\right)$ .

See the graph of the function $f(x)=x^3+x^2-9x-9$ in the attached image.

<h3>Constructing a graph</h3>

For constructing a graph we have the following steps:

Determine the range of values for x of your graph.

For this exercise, for example, we can define a range -4<x<4. In others words, the values of x will be in this interval.

Determine the points

Replace these x-values in the given equation. For example:

When x=-4, we will have: $\left(-4\right)^3+\left(-4\right)^2-9\left(-4\right)-9=-21$ . Do this for the all x-values of your ranges.

See the results for this step in the attached table.

Draw the graph

Mark the points <u>x</u> and<u> y</u> that you found in the last step. After that, connect the dots to draw the graph.

The attached image shows the graph for the given function.

<h3>Find the x- and y-intercepts</h3>

The intercepts are points that crosses the axes of your plot. From your graph is possible to see:

x-axis interception points (y=f(x)=0) are: $\left(-1,\:0\right),\:\left(-3,\:0\right),\:\left(3,\:0\right)$ .

y-axis interception point (x=0) is: $\left(0,\:-9\right)$ .

Learn more about intercepts of the graph here:

brainly.com/question/4504979

5 0

2 years ago

Two fair number cubes ate rolled. their sum is greater than 10 and one of the number is 6 which of the following best describes

Inga [223]

The answer is B not mutually exclusive

7 0

3 years ago

I need help with 7 and 9. It is almost due!!

otez555 [7]

The answer to question seven and question nine is

6 0

2 years ago

Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear

Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $\mu = 1.35$ .

The standard deviation is of $\sigma = 0.33$ .

Item 1:

Considering his ratio, we have that X = 0.73, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.73 - 1.35}{0.33}$

$Z = -1.88$

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1.96 - 1.35}{0.33}$

$Z = 1.85$

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

7 0

2 years ago