1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
docker41 [41]
2 years ago
12

For a statistics class project, a college student randomly samples 75 men who exercise at a gym regularly and 68 women who exerc

ise at a gym regularly. The college tudent believes that on average men spend more time at the gym each week. The college student records the number of minutes each person exercises in a given week. The college student conducts a hypothesis test at the 5% significance level.
Use the summary statistics to conduct a hypothesis test in StatCrunch. (Open an empty StatCrunch spreadsheet. Choose Stat, T Stats, two sample, with Summary. Adjust the alternative hypothesis as necessary Two Sample T-Test
Sample n Mean Std. Dev.
Men 75 65.7 13.9
Women 68 64.8 9.6
What conclusion can you draw from the output?
i. The data provide sufficient evidence to reject the null hypothesis and to conclude that the mean amount of exercise (minutes) is greater for men than for women at this gym.
ii. The data provide sufficient evidence to conclude that there is no difference in the mean number of minutes exercised per week for men and women.
iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym
Mathematics
1 answer:
raketka [301]2 years ago
4 0

Answer:

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

Step-by-step explanation:

1) The hypotheses are

H0: u1 ≤ u2 against the claim Ha: u1 > u2

The men spend less or equal time than the women  at the gym each week

vs

the men  spend greater time  than the women at the gym each week

2) The test statistic is

t= (x1`- x2`) / √ s1²/n1+ s2²/n2

t= 65.7- 64.8/√(13.9)²/75 + (9.6)²/68

t= 0.9/√2.57613 +1.35529

t=0.4539

and the degrees of freedom is

3) υ = [s₁²/n1 + s₂²/n2]²/ (s₁²/n1 )²/ n1-1 + (s₂²/n2)²/n2-1

=[(13.9)²/75 + (9.6)²/68]²/ [(13.9)²/75 ]² /74 + [ (9.6)²/68]²/67

= 139

The degrees of freedom is always rounded in this calculation

4) The Critical region is [1.656, ∞]

5) t-score is outside of the critical region, so there is not enough evidence to reject H₀.

iii. The data do not provide sufficient evidence to conclude that the mean number of minutes exercised per week is larger for men than for women at this gym

You might be interested in
Find the value of f(2) when f(x) = 4x+2
Sloan [31]

Answer:

the answer is 10

Step-by-step explanation:

f(2) that means the value of x= 2

the substitute x=2 in the 4(2)+2.Replace x with 2

6 0
3 years ago
What is the distance between 15 2/5 and -5 1/3?
Liono4ka [1.6K]

Answer:

hahahahahahaahahaha i dont know the answer i dont care to

Step-by-step explanation:

5 0
2 years ago
According to Chemical Engineering, an important property of fiber is its water absorbency. The average percent absorbency of 25
marusya05 [52]

Answer:

Step-by-step explanation:

3 0
3 years ago
The locations:
GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

AD = \sqrt{(-2 -6)^2 + (3 -8)^2}

AD = \sqrt{89}

CD = \sqrt{(10 -6)^2 + (2 -8)^2}

CD = \sqrt{52}

AB = \sqrt{(-2 -4)^2 + (3 +6)^2}

AB = \sqrt{117}

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
2 years ago
) Asuka travels at an average speed of 50 mph for 20 miles.
Anuta_ua [19.1K]

Answer: 41.86 miles/hour

Step-by-step explanation:

Use Distance = Speed*Time to find the two missing values with the data that is provided for those two cases [<em>in brackets</em>].

MPH MILES     HOURS

 50            20      [<em>0.4]</em>

 [<em>40</em>]    <u>70</u>      <u>1.75</u>

Totals   90 miles   2.15 hours

Average = 90 miles/2.15 hours

     41.86 mph

5 0
3 years ago
Other questions:
  • Simplify the expression.
    11·1 answer
  • JUANITA WANTS TO PARTICIPATE IN A 20 KILOMETER BICYCLE RACE. SHE IS CONSIDERING TWO TRAINING PROGRAMS BELOW. PROGRAM A: RIDE 10
    7·1 answer
  • According to the fundamental theorem of algebra, how many zeros does the function f(x)=4x^3-x^2-2x+1 have?
    8·1 answer
  • I need help asap :):);)
    14·1 answer
  • Please help me with #2!!!!
    13·1 answer
  • What is the area of the sector shown in the diagram below?
    14·1 answer
  • What is 18-2x(4 3) i need the answer?
    11·1 answer
  • The following are test scores Karen received during the first marking period.
    7·1 answer
  • Kendal has a 5-pound bag of flour that holds 1812 cups.
    12·1 answer
  • Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. Solve the inequality. E
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!