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Alexeev081 [22]
3 years ago
10

HELP PLSSSSSSS ILL GIVE YOU BRAINLIST

Mathematics
1 answer:
Allushta [10]3 years ago
5 0

Answer:

ewdhyredhkiydg

Step-by-step explanation:

ggdsdhudgjjthfd

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What is the multiplicative inverse of -27 and what is the multiplicative inverse for 7/9 and -9/16
liberstina [14]

The multiplicative inverse of a number is the number when you multiply it, it gives you the product of 1.

So for - 27, what number will give us 1 when we multiply it by -27

-27 * -1/27 = 1

So the multiplicative inverse of -27 = -1/27

7/9 * 9/7 = 1

-9/16 * -16/9 = 1

So in essence, just take the number and flip it

-27 = -1 / 27

7/9 = 9/7

-9/16 = -16/9

3 0
3 years ago
Alex, Bob, and Cole have a combined weight of 111 kilograms. If Alex weighs 44 kg, and Bob weighs three-forth of Alex's weight,
vlabodo [156]

Answer:34

Step-by-step explanation:

Weight of Alex:44

Weight of Bob:44*(3/4)

=33

Combined weight of all of them:111

Combined weight of Alex and Bob=44+33=77

Cole's weight=111-77 =34

8 0
3 years ago
I need help quickly. I think it's B or D.
Ludmilka [50]

personally id say c cuz the one on the right makes it have no trend, and also because if it was a negative trend there should only have been one answer on it really.

5 0
3 years ago
Read 2 more answers
M/J Grade 8 Pre-Algebra-PT-FL-1205070-003
Andreas93 [3]

Answer:

Following are the description of the given course code:

Step-by-step explanation:

The given course code is Pre-Algebra, which is just an introduction arithmetic course programs to train high school in the Algebra 1. This course aims to strengthen required problem solving skills, datatypes, equations, as well as graphing.

  • In this course students start to see the "big picture" of maths but also understand that mathematical, algorithmic, and angular principles are intertwined to form a basis for higher mathematics education.
  • The duration of this code is in year and it is divided into two levels. In this, code it includes PreK to 12 Education Courses , with the general mathematics .
5 0
3 years ago
Pls help with 29..tank you
trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the  2 roots be  A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 =  ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 =  3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

 

3 0
3 years ago
Read 2 more answers
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