3 years ago

Please help me with my delta math

Mathematics

1 answer:

astra-53 [7]3 years ago

5 0

Answer:

Use “ Math- way”

Step-by-step explanation:

It’s a web browser made for this stuff, you‘re welcome

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If m∠RQS=22x-11 and m∠RQT=12x-8, find m∠TQS

Arada [10]

Answer:

∡TQS = 10x -3

Step-by-step explanation:

∡TQS = ∡RQS - ∡RQT

= 22x - 11 - (12x - 8)

= 10x -3

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3 years ago

What are the solutions to the quadratic equation 4x2 + 28x = 0?

AleksandrR [38]

Answer:

x is 0 or -7

Step-by-step explanation:

$4x^{2} +28x=0\\4x(x} +7)=0\\4x=0 x=0\\x+7=0\\x=-7$

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Add the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending powers o

tresset_1 [31]

ANSWER
$13 {x}^{3} - 2 {x}^{2} + 3x + 13$

EXPLANATION

The first polynomial is
$5 {x}^{3} + 3 {x}^{2} - 5x + 4$

The second polynomial is
$8 {x}^{3} - 5 {x}^{2} + 8x + 9$

If we add the two polynomials we obtain,

$(5 {x}^{3} + 3 {x}^{2} - 5x + 4) + (8 {x}^{3} - 5 {x}^{2} + 8x + 9)$

Next we group like terms to obtain,

$5 {x}^{3} + 8 {x}^{3}+ 3 {x}^{2} -5 {x}^{2} - 5x + 8x + 9 + 4$

We simplify the to obtain,

$13{x}^{3} -2{x}^{2} + 3x + 13$

This is the sum of the two polynomials in descending powers of
$x$

Descending means from the highest power to the least.

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