Assume (a,b) has a minimum element m.
m is in the interval so a < m < b.
a < m
Adding a to both sides,
2a < a + m
Adding m to both sides of the first inequality,
a + m < 2m
So
2a < a+m < 2m
a < (a+m)/2 < m < b
Since the average (a+m)/2 is in the range (a,b) and less than m, that contradicts our assumption that m is the minimum. So we conclude there is no minimum since given any purported minimum we can always compute something smaller in the range.
Answer:
0.99
Step-by-step explanation:
1.98 - 0.99 is 0.99.
Easy.
Just do it like you would any other problem.
Answer:
um can i see the statements?
Step-by-step explanation:
Answer:
-2+11x
Step-by-step explanation:
Combine like terms
(-5+3)+(x+10x)
-5+3 = -2
x+10x = 11x
-2+11x
