You take a trip by air that involves three independent flights. if there is an 76% chance each specific leg of the trip is on ti
me, what is the probability all three flights arrive on time?
1 answer:
I think around 44% chance that all three flights would arrive on time, but i'm not that sure.
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The answer is 14.4% I just did it in my head
-2x+12 because you gotta distribute your -2 to the rest of the equation.
-9 + 10 over 4 = -7
1/4 = -7
1/4 does not equal -7
X= 3 y=3
(3)2x+y=9
4x-3y=3
6x+3y=27
4x-3y=3
——————
10x=30
—————-
10
x=3
2(3)+y=9
6+y=9
-6. -6
y=3
The first thing we must do is calculate the circumeference:
now, calculate the angle of arc
360° = 49.612
360° - 66.4° - 180° = x
x = 113.6°
now, to calculate the arc length it would be:
