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Cerrena [4.2K]
3 years ago
10

In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key r

equirements includes certification and accreditation, which is a process that occurs after the system is documented, controls tested, and risk assessment completed. It is required before going live with a major system. Once a system is certified and accredited, responsibility shifts to the owner to operate the system. True False
Computers and Technology
1 answer:
lesya692 [45]3 years ago
8 0

Answer:

True

Explanation:

In order to be compliant with the NIST publications, policies must include key security control requirements. One of these key requirements includes certification and accreditation, which is a process that occurs after the system is documented, controls tested, and risk assessment completed. It is required before going live with a major system. Once a system is certified and accredited, responsibility shifts to the owner to operate the system is a true statement.

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You manage a small LAN for a branch office. The branch office has three file servers and few client workstations. You want to us
lana66690 [7]

You manage small LAN for a branch office. The branch office has three file servers and few client workstations. You want to use Ethernet device and offer guaranteed bandwidth to each server. You design the network by <u>connecting all network devices to a switch. Connect each server to its own switch port.</u>

<u></u>

Explanation:

  • A local-area network (LAN) is a computer network that spans a relatively small area.
  • Most often, a LAN is confined to a single room, building or group of buildings, however, one LAN can be connected to other LANs over any distance via telephone lines and radio waves.
  • The LAN is the networking infrastructure that provides access to network communication services and resources for end users and devices spread over a single floor or building.
  • Designing a LAN for the campus use case is not a one-design-fits-all proposition.
  • If there is a single 48-port switch, 47 devices can be supported, with only one port used to connect the switch to the rest of the network, and only one power outlet needed to accommodate the single switch

8 0
3 years ago
Computer works on the basis of?​
ASHA 777 [7]
Computer works on the Basis of multitasking.
6 0
2 years ago
Write a function that returns a chessboard pattern ("B" for black squares, "W" for white squares). The function takes a number N
Kryger [21]

Answer:

Here is the C++ program.

#include <iostream>  //to use input output functions

using namespace std;  // to access objects like cin cout

 

void chessboard(int N){  // function that takes a number N as parameter generates corresponding board

   int i, j;  

   string black = "B";  // B for black squares

   string white = "W"; // W for white squares

   for(i=1;i<=N;i++){  //iterates through each column of the board

       for(j=1;j<=N;j++){  //iterates through each row of the board

           if((i+j)%2==0)  // if sum of i and j is completely divisible by 2

               cout<<black<<" ";  //displays B when above if condition is true

           else  //if (i+j)%2 is not equal to 0

           cout<<white<<" ";  }  // displays W when above if condition is false

      cout<<endl;    }    }  //prints the new line

       

int main(){    //start of the main function

   int num;  //declares an integer num

   cout << "Enter an integer representing the size of the chessboard: ";  //prompts user to enter size of chess board

   cin >> num;  //reads value of num from user

   chessboard(num); } //calls chessboard function to display N lines consist of N space-separated characters representing the chessboard pattern

Explanation:

The function works as follows:

Lets say that N = 2

two string variables black and white are declared. The value of black is set to "B" and value of white is set to "W" to return a chessboard pattern in B and W squares.

The outer loop for(i=1;i<=N;i++) iterates through each column of the chess board. The inner loop  for(j=1;j<=N;j++) iterates through each row of chess board.

At first iteration of outer loop:

N = 2

outer loop:

i=1

i<=N is true because i=1 and 1<=2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+1) % 2 == 0

(1+1 )% 2 takes the mod of 1+1 with 2 which gives the remainder of the division.

2%2 As 2 is completely divisible by 2 so 2%2 == 0

Hence the if condition evaluates to true. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(1+2) % 2 == 0

(1+2 )% 2 takes the mod of 1+2 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop to iterate through the next row.

At second iteration of outer loop:

N = 2

outer loop:

i=2

i<=N is true because i=2 and 2 = 2

So the program enters the body of the outer for loop. It has an inner for loop:

for(j=1;j<=N;j++)

At first iteration of inner loop:

j = 1

j<=N is true because j=1 and 1<=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+1) % 2 == 0

(2+1 )% 2 takes the mod of 2+1 with 2 which gives the remainder of the division.

3%2 As 3 is not completely divisible by 2

Hence the if condition evaluates to false. So the statement in else part executes:

cout<<white<<" ";

This prints W on the output screen with a space.

B W

W

The value of j is incremented to 1.

j = 2

At second iteration of inner loop:

j = 2

j<=N is true because j=2 and 2=2

So the program enters the body of the inner for loop. It has an if statement:

if((i+j)%2==0) this statement works as:

if(2+2) % 2 == 0

(2+2 )% 2 takes the mod of 2+2 with 2 which gives the remainder of the division.

4%2 As 4 is completely divisible by 2 so 4%2 == 0

Hence the if condition evaluates to false. So the statement in if part executes:

cout<<black<<" ";

This prints B on the output screen with a space.

B W

W B

The value of j is incremented to 1.

j = 3

Now  

j<=N is false because j=3 and 3>2

So the loop breaks and program moves to the outer loop. The value of outer loop variable i is incremented to 1 so i = 3

N = 2

outer loop:

i=3

i<=N is false because i=3 and 3>2

So this outer loop ends.

Now the output of this program is:

B W

W B

Screenshot of this program along with its output is attached.

8 0
2 years ago
When you send an email how many computers does it go to
Xelga [282]

once you have sent the email it will only go to the server which then the person receiving it would log on therefore requesting the emails recived.

I'm not 100% sure my answer is classed as correct but I would say it doesn't go to a computer it just gets stored on a server in till requested

4 0
3 years ago
What is desktop computer? <br> ​
butalik [34]

Answer:

a computer suitable for use at an ordinary desk.

noun: desktop computer

"a new low-end desktop"

Explanation:

please mark me as a brainly

3 0
2 years ago
Read 3 more answers
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