Answer:
The image on the left is unicellular. Unicellular means to be made of one cell and the two on the right are multicellular, made of multiple cells.
Answer:
SNPs have shown that only 0.1 % of DNA sequences are different in the human genome between different individuals, thereby all the inherited phenotypic variation observed in our species is associated with only 0.1 % of differences at the genome level
Explanation:
Haplotypes are block-like sequences of DNA that are inherited together due to low recombination rates. Moreover, single-nucleotide polymorphism (SNP) mapping is a very useful methodology used to map the site of SNP mutations (i.e., SNP variants). In this regard, it has been observed that there are approximately 10 million common SNPs in the human genome. These SNPs contribute to the wide range of phenotypic variation observed in human populations for different traits (e.g., eye color, hair, weight, height, etc). Moreover, researchers have determined that SNPs can be clustered into haplotypes, thereby haplotypes can be accurately sampled by as few as approx. 300,000 selected SNPs, which are sufficient to represent all of the genetic variation across different human genomes.
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
