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3 years ago

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Denise bought a T-shirt at the sale price of $24. The original cost of a T-shirt was $40. What percent represents the discount t

hat Denise received when buying the T-shirt?

1 answer:

RoseWind [281]3 years ago

3 0

Answer:

Step-by-step explanation:

we subtract to find how much they saved, 40-24=16

now we divide 16 by 40 to get the percent 16/40 = 0.4

40%

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Hi, can someone please help, and possibly explain the answer please.

mr_godi [17]

Answer:

$x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

Step-by-step explanation:

Quadratic formula: $x=\frac{-b\±\sqrt{b^2-4ac} }{2a}$ when the equation is $0=ax^2+bx+c$

The given equation is $1=-2x+3x^2+1$ . Let's first arrange this so its format looks like $y=ax^2+bx+c$ :

$1=-2x+3x^2+1$

$1=3x^2-2x+1$

Subtract 1 from both sides of the equation

$1-1=3x^2-2x+1-1\\0=3x^2-2x+0$

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

$x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}$

I hope this helps!

8 0

3 years ago

Easy I am just not sure on how to solve it please give answer and how I would solve it

Elina [12.6K]

You want to compare the square root of 55 using "mental math". Start off by choosing two perfect squares that you can think of that are close to 55.

If you don't know perfect squares then start with the number 2 and multiply it by itself. 2 times 2 equals 4, so 4 is a perfect square.

Take the number 3, multiply it by itself, and so on. Do this for all the numbers until you find two perfect squares that are close to 55.

The two perfect squares closest to 55 are the square roots of 49 and 64. Find the square root of these numbers.

√49 = 7

√64 = 8

Calculate how far 55 is from 49 and 64. 55 is 6 digits away from 49 and 9 digits away from 64.

This means the square root of 55 will be closer to the square root of 49; 7. Since we know that it will be closer to 7, you can put the less than sign for your answer.

√55 < 7.7

(The actual square root of 55 is ~7.4, so we were correct in determining the answer without using a calculator!)

6 0

3 years ago

Read 2 more answers

Using the numbers 5, 8, and 24, create a problem using no more than four operations (adding, subtracting, multiplication, divisi

Alik [6]

The given three numbers are 5,8,24.

We have to use four operations (Adding, Subtracting,multiplication, division, square, square root, cube, cube root) out of these operation to make the result an irrational number.

$1. \sqrt{\frac{24}{8}} + 5=\sqrt{3}+5,\\\\2. \sqrt{\frac{24}{8}} - 5=\sqrt{3} -5 \\\\ 3.\sqrt{\frac{24 \times 5}{8}}=\sqrt{15} \\\\ 4. (5 \times 8 \times 24)^\frac{1}{3}$

There are many more examples that you can write.

Keep in mind

1. Sum of Rational and irrational is always irrational.

2. Difference of rational and irrational is always irrational.

As none of the 5,8,24 is a perfect square , nor addition of any two results in a perfect square, so square root of their addition or subtraction or multiplication results in an irrational number.

Similarly ,apart from 8, none of 5,24 is a perfect cube.So if you add or subtract any number from 8 and take their cube root or square root ,results in an irrational number.

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3 years ago

Read 2 more answers

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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3 years ago

Can somebody help me What is 4(x-1)=6

avanturin [10]

4(x-1)=6 you start by dividing the whole equation by 4, so
x-1=6/4 simplify, x-1=3/2 then you add 1 to the whole equation
x=1 and 3/2 or x=5/2

7 0

3 years ago