So if it is 1 1/2 you go to 1 then halfway towards 2
Answer:
None of those answers are correct
Step-by-step explanation:
There are no real solutions
Let's solve your equation step-by-step.
2+2x−3
2x+3
=
3x+4
x+2
Step 1: Cross-multiply.
2+2x−3
2x+3
=
3x+4
x+2
(2+2x−3)*(x+2)=(3x+4)*(2x+3)
2x2+3x−2=6x2+17x+12
Step 2: Subtract 6x^2+17x+12 from both sides.
2x2+3x−2−(6x2+17x+12)=6x2+17x+12−(6x2+17x+12)
−4x2−14x−14=0
For this equation: a=-4, b=-14, c=-14
−4x2+−14x+−14=0
Step 3: Use quadratic formula with a=-4, b=-14, c=-14.
x=
−b±√b2−4ac
2a
x=
−(−14)±√(−14)2−4(−4)(−14)
2(−4)
x=
14±√−28
−8
Answer:
No real solutions.
Answer:
The expected number of days until prisoner reaches freedom is 12 days
Step-by-step explanation:
From the given information:
Let X be the random variable that denotes the number of days until the prisoner reaches freedom.
We can evaluate E(X) by calculating the doors selected, If Y be the event that the prisoner selects a door, Then;
E(X) = E( E[X|Y] )
E(X) = E [X|Y =1 ] P{Y =1} + E [X|Y =2 ] P{Y =2} + E [X|Y =3 ] P{Y =3}
Solving for E[X]; we get
E[X] = 12
The original equation:
Integral of csc(5x)
Use a u sub:
u = 5x
du = 5dx
Simplify the du:
Apply to the equation:
Integral csc(u)
du
Simplify:
Integral
du
Factor out the constant:
Integral
du
Use a second Substitution:
v = tan(
)
du =
dv
Applying to the equation:
Simplify:
Integrate:
Insert back in your v and u:
v = tan(
)
u = 5x
This gives us the final equation (don't forget your constant):
(Thank you for making me write it out, I made a mistake on the original answer.)
The answer is x=1 because you have to distribute and then divide