The height of the roof is <u>3.57m</u>
Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.
Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.
The length of the window s is given by,
The first drop is at the bottom and it takes 5t seconds to reach down.
The height of the roof h is the distance traveled by the first drop and is given by,
the height of the roof is 3.57 m
Speed of light= wavelenght * frequency
Frequency = (3x10^8)/(1 x 10^-4)
= 3 x 10^+12
Answer:
So airplane will be 1324.9453 m apart after 2.9 hour
Explanation:
So if we draw the vectors of a 2d graph we see that the difference in angles is = 83 - 44.3 = 
Distance traveled by first plane = 730×2.9 = 2117 m
And distance traveled by second plane = 590×2.9 = 1711 m
We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 38.7.
Using the law of cosine, 
representing the distance between the planes, we see that:
d = 1324.9453 m
Answer:
Option C is the correct answer.
Explanation:
We equation for elongation
Here we need to find load required,
We need to double the wire, that is ΔL = 2L - L = L
A = 5 x 10⁻⁵ m²
E = 2 x 10¹¹ N/m²
Substituting
Option C is the correct answer.
