Answer:
Maximum amount of heat = 10002151.38J
Explanation:
Workdone by motor in 86.1 minutes I given by:
W = power × time
W= 294 × 86.1×60
W= 1439424 Joules
W= 1.4 ×10^6Joules
The amount of heat extracted is given by:
/QL /= K/W/ = TL/W/ /(TH - TL)
Where TL= freezing compartment temperature
TH = Outside air temperature
/QL /= 271 × 1439424 / (310 - 271)
/QL/ = 390083904/39
/QL/ = 10002151.38 Joules
Explanation:
A. Walk the person around
Explanation:
As the given data is as follows.
ohm
,
ohm,
= 1200
(as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance = 
=
ohm
= 2600 ohm
or, = 2.6
ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6
ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance = 
= 
=
ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is
ohm.
Work = Force * distance
Force = 70 N
Work = 3500 J
3500 = 70d
d = 3500/70 = 50 m