D I might be wroung .....i think this so the answer because biotic are all living things and bacteria is living
Answer:
Technician A and Technician B are correct.
Explanation:
Answer:
L = 0 m
Therefore, the cricket was 0m off the ground when it became Moe’s lunch.
Explanation:
Let L represent Moe's height during the leap.
Moe's velocity v at any point in time during the leap is;
v = dL/dt = u - gt .......1
Where;
u = it's initial speed
g = acceleration due to gravity on Mars
t = time
The determine how far the cricket was off the ground when it became Moe’s lunch.
We need to integrate equation 1 with respect to t
L = ∫dL/dt = ∫( u - gt)
L = ut - 0.5gt^2 + L₀
Where;
L₀ = Moe's initial height = 0
u = 105m/s
t = 56 s
g = 3.75 m/s^2
Substituting the values, we have;
L = (105×56) -(0.5×3.75×56^2) + 0
L = 0 m
Therefore, the cricket was 0m off the ground when it became Moe’s lunch.
Answer:
Explanation:
Hubble's law is considered the first observational basis for the expansion of the universe and today serves as one of the pieces of evidence most often cited in support of the Big Bang model.The motion of astronomical objects due solely to this expansion is known as the Hubble flow.
The correct answer here is that the cell would most likely be classified
as a eukaryotic cell. This can be determined due to the fact that there
are membrane-bound organelles within the cell, so we know that this is a
eukaryotic cell rather than a prokaryotic cell because because
organelles are not needed within prokaryotic cells.