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Naily [24]
3 years ago
6

What is 96 divided by 4977 long divided

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Answer:

Your answer is: 51 with a remainder of 81

Or = 1659/32

Step-by-step explanation:

Hope this helped : )

aalyn [17]3 years ago
7 0

Answer:

51.8375

Step-by-step explanation:

you first see if you can divie 96 into 49 no so you go to next one. Can 96 go in to 497 yes so how many times? Then after that you will get a left over then divied he left over by 96 to get your answer.

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9 over 6 as a percent
stiv31 [10]
150%. since you already have 6, that's 100%. the extra 3 is half of the 6, meaning that it would be 50%
8 0
3 years ago
Read 2 more answers
The sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab 2. if one addend is –5a2b2 12a2b – 5, what is the other addend? 15a2b2 –
Brrunno [24]

The other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is real number).

The sum of two polynomials is,

10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2

The one polynomial addend is,

-5a^2b^2 +12a^2b - 5

Let suppose the other polynomial addend is f(a,b). Thus,

(-5a^2b^2 +12a^2b - 5)+f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)

Isolate the second polynomial as,

f(a,b)=(10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2)-(-5a^2b^2 +12a^2b - 5)\\f(a,b)=10a^2b^2 - 8a^2b+ 6ab^2 - 4ab+2+5a^2b^2 -12a^2b + 5

Arrange the like terms as,

f(a,b)=10a^2b^2+5a^2b^2 - 8a^2b -12a^2b+ 6ab^2 - 4ab + 2+5\\f(a,b)=15a^2b^2- 20a^2b + 6ab^2 - 4ab + 7

Hence, the other polynomial addend, when the sum of two polynomials is 10a2b2 – 8a2b 6ab2 – 4ab  is 15a²b²- 20a²b + 6ab² - 4ab + 7.

Learn more about polynomial here;

brainly.com/question/24380382

7 0
2 years ago
The ratio of 6 kg to 600 gram is​
zloy xaker [14]

Answer:

10:1

Step-by-step explanation:

as 6 kg = 6000g

so 6000g /600g

= 10 : 1. { 10 /1)

7 0
3 years ago
Evelyn's made a cake in the shape of a circus tent the cake consisted of a cylinder and a cone .The height of the cone is half t
Lera25 [3.4K]
The volume of the cake is 1470 in³. 
volume of a cylinder = πr² x height
(Think about how a cylinder is basically a bunch of circles stacked on top of each other. To find the volume, first you need the area of the circle (πr², then you multiply by how many circles you are stacking on top of each other (height)) 

we know the diameter of the cylinder is 12 in. and the radius is half of the diameter. 
half of 12 is 6, therefore the radius is 6 in. or r = 6 
Assuming pi is 3.14, solve for the height of the cylinder
1470 = (3.14)(6²)(height)
1470 = 3.14 x 36 x height
1470 = 113.04 x height
height ≈ 13 in

Now that we know the height of the cylinder is about 13 in., we know the height of the cone, because the problem says that the height of the cone is half the height of the cylinder. 
half of 13 is 6.5, therefore the height of the cone is 6.5 
the radius of the cone is the same as that of the cylinder, 6 in. 

volume of a cone = πr² × (height ÷ 3)

volume of the cone = (3.14)(6²)(6.5 ÷ 3)
volume of the cone = (3.14)(36)(2.16666)
volume of the cone = 244.92 in³

Now all that's left to find the volume of the whole cake is to add the volume of the cylinder to the volume of the cone. 

1470 + 244.92 = 1714.92 in³



6 0
3 years ago
Please help me on this
Leni [432]
5 7/8 is the answer to the problem
4 0
4 years ago
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