C) monochromatic
Hope this helps!
btw make me brainliest?
Answer:
a. 1 is a packet, 2 is data, 3 is a frame.
Explanation:
And what is not mentioned is segment which used TCP/UDP and is part of Transport layer. The packet carries the destination and sender IP address, and is part of the Network Layer. The frame has the Mac address of destination device and senders device and is part of data link layer.
Hence segment has no IP address, hence b. is not correct. Also, data cannot have the IP Address, and Frame has the MAC address, Hence, the above answer. And this arrangement is part of Data Encapsulation.
Also keep in mind data can be anything like a series of bits, or any and it can or not have a header.
If you include all zeroes, then it should be 1,000,000,000. Otherwise it’s 999,999,999.
Think of how between 0-9 theres 10 numbers, and use that logic towards 000000000-999999999
Answer:
Option a, b, d, f, and j is legal method calls.
Explanation:
In the given question some information is missing, that is the method definition which can be described as follows:
Method definition:
int x =2, y=3; //defining integer variable
int mathMethod (int x) //method definition
{//method body
int z=x+y; //calculate value
return z; //return value
}
In the given question option a, b, d, f, and j is legal, because these options follow the correct syntax, and other option were incorrect which can be defined as follows:
- In option c, It is illegal because it accepts only one parameter.
- In option e, It is accepts long number, that's why it is illegal.
- In option g, It accepts float value, that's why it is illegal.
- In option h, It doesn't accepts any parameter.
- In option i, It isn't use in method.
Answer:
parentheses
Explanation: hope i helped <3 °ω°
