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posledela
3 years ago
5

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42m​-by-42m squ

are. Val says the area is 1005.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have​ made?
Thanks in advance!
I don't have anymore points so please make a good and accurate answer.
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0

Answer:

Area of the enclosed figure = 3148.74 m^{2}

Step-by-step explanation:

Area enclosed by the figure = 2 x area of the semicircle + area of the square

For the semicircle,

radius = \frac{diameter}{2}

          = \frac{42}{2}

          = 21 m

area of a semicircle = \frac{1}{2} x \pi r^{2}

                                = \frac{1}{2} x 3.14 x (21)^{2}

                                = 692.37 m^{2}

area of a square = length x length

                            = 42 x 42

                            = 1764 m^{2}

Thus,

area enclosed by the figure = 2 x 692.37 + 1764

                                              = 3148.74 m^{2}

The total area enclosed bu the figure is 3148.74 m^{2}

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