Question

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42m​-by-42m square. Val says the area is 1005.48 m^2. Find the area enclosed by the figure. Use 3.14 for pi. What error might Val have​ made?
Thanks in advance!
I don't have anymore points so please make a good and accurate answer.

Answer 1

Answer:

Area of the enclosed figure = 3148.74 $m^{2}$

Step-by-step explanation:

Area enclosed by the figure = 2 x area of the semicircle + area of the square

For the semicircle,

radius = $\frac{diameter}{2}$

          = $\frac{42}{2}$

          = 21 m

area of a semicircle = $\frac{1}{2}$ x $\pi r^{2}$

                                = $\frac{1}{2}$ x 3.14 x $(21)^{2}$

                                = 692.37 $m^{2}$

area of a square = length x length

                            = 42 x 42

                            = 1764 $m^{2}$

Thus,

area enclosed by the figure = 2 x 692.37 + 1764

                                              = 3148.74 $m^{2}$

The total area enclosed bu the figure is 3148.74 $m^{2}$