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Harrizon [31]
3 years ago
14

An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio

n fee plus $0.75 per ride. For how many rides do the two options have the same cost ( or, what is the break-even point)?
Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

                Each ride = $0.50

Option 2 . Admission fee = $6

                Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x  ---1

Cost of ride according to option 2 = 0.75x  

So, total cost after having x rides according to option 2 :

= 6+0.75x  --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

10+0.50x=6+ 0.75x

10-6= 0.75x-0.50x

4= 0.25x

\frac{4}{0.25} =x

16=x

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

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