Answer:
Step-by-step explanation:
We are to rank the options given in the question to correctly prove the theorem that: "If A & B are set, and A is a subset of B"
To arrange the steps in the correct order, we have:
(a) Assume that B is countable
(b) The elements of B can be listed as b1, b2, b3
(c) Since A is a subset of B, taking the subsequence of {bn} that contains the terms that are in A gives a listing of the elements of A.
(d) Therefore A is countable, contradicting the hypothesis.
(e) Thus B is not countable
Let the number be x,
(1/2)x=1+(1/3)x
Solving for x,
(1/2)x-(1/3)x=1+(1/3)x-(1/3)x
(1/2)x-(1/3)x=1
(1*3/6)x-(1*2/6)x=1
(3/6)x-(2/6)x=1
(1/6)x=1
6*(1/6)x=6*1
Therefore, x=6
Slope for the function is -1/3.5.
It is - 16 because adding two negatives give you a negative
Answer:
Step-by-step explanation:
1. Substitute p for 5p+4
2. 5p+4-11
3. 5p-7