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2 years ago

12

Movement of our arms and legs is possible when muscles pull on our _________________________________.

1 answer:

cricket20 [7]2 years ago

5 0

Answer:

Isn't this supposed to be a science question

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Plz help me with these math questions

Akimi4 [234]

For b on the first paper you will start with the distribution property and multiply both x and 2 by 3 because they are in the ()
now you have 3x+ 6=x-18
from here you can subtract x from both sides
2x+6=-18
next subtract 6 from both sides
2x=-24
divide both sides by 2...
x=-12
hope this helped

8 0

2 years ago

SOS EASY MATH PLZ PLZ

Alborosie

A isn’t correct because there is 2 O’s on the left side and 3 on the right
B is incorrect because there is an S on the right but not on the left
C is incorrect because there are 2 Ca on the left side and 1 on the right
D is balanced as there are 2Na ok each side, 2Cl on each side,2H, and 1 SO4 on each side

7 0

3 years ago

Read 2 more answers

Given: y= 2x + 1 and - 4x + y = 9,<br> solve the system by substitution

kicyunya [14]

Answer:

x=-4 y=-7

Step-by-step explanation:

-4x+y=9 get y alone

add 4x both sides

y=4x+9

insert into y=2x+1

2x+1=4x+9

subtract 1 both sides

2x=4x+8

subtract 4x both sides

-2x=8

divide by -2

x=-4

y=2x+1

y=2(-4)+1

y=-8+1

y=-7

check

-4(-4)+(-7)=9

-16+(-7)=9

9=9

x=-4

y=-7

gl

6 0

2 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

3 years ago

. 3x 5 - 2x-14х<br> х+2 К-4 х 2х8

vitfil [10]

. 3x 5 - 2x-14х
х+2 К-4 х 2х8
=5

7 0

2 years ago