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Vsevolod [243]
3 years ago
11

The following set of ordered pairs represent a function:

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0
Eeeeeeeeeeeeeeeeeeeeeeeee
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Please help i’ll give brainliest
Furkat [3]

Answer:

The answer is A, a total of 12 students spend 31 or more hours online per month.

Step-by-step explanation:

From the hours of 31 to 65 there are twelve students.

7 0
3 years ago
It costs $5.08 for 4 pounds of gummy candy in bulk. How much would it cost to buy 17 pounds?
Daniel [21]

Answer:

$21.59

Step-by-step explanation:

Basically how I did it was to multiply 5.08 by 4, because that would be the cost of 16 bags and then I divided 5.08 by 4 to see how much one bag would cost. One bag costs 1.27. After I've got the answer, I added 1.27 to 20.32 and got $21.59.

5 0
3 years ago
Prove by factorization √16×81=√16×√81
Oksanka [162]

Answer:

√16×81 = 4×9 or √1296 = 36

√16×√81 = 4×9 = 36

Step-by-step explanation:

√81×16

We simplify 81 and 16 by prime factorisation (expressing a number as a product of its prime factors).

√81 = √3×3×3×3 = √9×9 = √9² = 9

√16 = √2×2×2×2 = √4×4 = √4² = 4

4 0
3 years ago
A rocket is launched from the top of a 70 foot cliff with an initial velocity of 130 feet per second. The height, h, of the rock
lana [24]

Answer:

The answer is 7.8 seconds.

  1. Solve for t in the equation using the Quadratic formula.
  2. Eliminate the negative solution and the positive solution is your answer.

Please Mark Brainliest If This Helped!

6 0
2 years ago
Whats the answer to 2y^0-(3y)^0
mrs_skeptik [129]

Answer:

1

Step-by-step explanation:

To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:

2y^0 - (3y)^0

= 2(1) - (1)

= <u>1</u>

<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>

6 0
3 years ago
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