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den301095 [7]
3 years ago
12

the function y=-2(x-3)^2+4 shows the daily profit (in hundreds of dollars) of a hot dog stand, where x is the price of a hot dog

(in dollars). Find and interpret the 0's of this function.
Mathematics
1 answer:
Roman55 [17]3 years ago
8 0
X intercept would mean plug in 0 for Y.
Then finding the y intercept would mean X is 0. Your answer will be 69420
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Please help me with this question
Nostrana [21]

Answer:

y= 3× -9

Step-by-step explanation:

i hope it helped :)

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PLS HELP SUPER EASY!<br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B125%7D" id="TexFormula1" title="\sqrt[4]{125}" a
Yuki888 [10]

The fourth root? There is no simplifying to be done.

The only way to continue work on this is converting to decimal. To four places the answer is 3.3437.

If you meant to ask for the cube root, the answer is 5.

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givi [52]

Answer:

(-10)^33

Step-by-step explanation:

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Use ΔJKL and ΔMPN to determine whether Don's claim is true or false.
denpristay [2]

Answer:

I think is SSS

Step-by-step explanation:

SSS Similarity Theorem. By definition, two triangles are similar if all their corresponding angles are congruent and their corresponding sides are proportional. ... SSS Similarity Theorem: If all three pairs of corresponding sides of two triangles are proportional, then the two triangles are similar.

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3 years ago
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A student wanted to estimate the number of chocolate chips in a commercial brand of cookie. He sampled 100 cookies and found an
m_a_m_a [10]

Answer: A. (8.4,12.6)

Step-by-step explanation:

Confidence interval(\mu) is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

, where n is the sample size

\sigma = Population standard deviation.

\overline{x}= Sample mean

z_{\alpha/2} = Two tailed z-value for significance level of \alpha.

Given : Confidence level = 99% = 0.99

Significance level = \alpha=1-0.99=0.01

By standard normal z-value table ,

Two tailed z-value for Significance level of 0.01 :

z_{\alpha/2}=z_{0.005}=2.576

Also,

n=100

\sigma= 8

\overline{x}=10.5

Then, the required 99% confidence interval for the average number (\mu) of chips per cookie :-

10.5\pm (2.576)\dfrac{8}{\sqrt{100}}\\\\ =10.5\pm 2.0608\\\\=(10.5-2.0608,\ 10.5+2.0608)=(8.4392,\ 12.5608)\approx(8.4,\ 12.6)

Hence, the 99% confidence interval for the average number of chips per cookie = (8.4,12.6)

5 0
2 years ago
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