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olya-2409 [2.1K]

2 years ago

7

Which speed is the fastest? A 18 feet in 20 minutes B 90 feet in 2.5 hours C 20 yards in 1.5 hours D 3 2/3 yards in 15 minutes

1 answer:

Andre45 [30]2 years ago

7 0

To solve, put each answer in terms of ft/min. Do this by converting all distances to feet and times to minutes, the dividing feet by minutes. A) $18/20=9/10$ ft/min. B) To get 2.5 hrs to mins, multiply by 60. $2.5*60=150$ $90/150=3/5$ ft/min. C) To get feet from yards, multiply yards by 3. $20*3=60$ $1.5*60=90$ $60/90=2/3$ ft/min. D) $(11/3)*3=11$ $11/15=11/15$ ft/min. Now compare the fractions to determine the largest and fastest is 9/10 ft/min, or A.

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s344n2d4d5 [400]

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explanation:

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43.77 as a mixed number in simplest form

valina [46]

First you have to take the whole number (43) and then take the decimal and put it over 100 (77/100).

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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)

poizon [28]

$(x+2)^{2}$ + $(y-5)^{2}$ = 34

The equation of a circle in standard form is

$(x-a)^{2}$ + $(y-b)^{2}$ = $r^{2}$

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [ $\frac{1}{2}$ (x $x_{1}$ + $x_{2}$ , $\frac{1}{2}$ ( $y_{1}$ + $y_{2}$

where ( $x_{1}$ , $y_{1}$ =(3,8) and ( $x_{2}$ , $y_{2}$ =(-7,2)

centre = ( $\frac{1}{2}$ (3-7), $\frac{1}{2}$ (8+2)) = (-2,5)

Calculate r using the distance formula

r = √( $x_{2}$ - $x_{1}$ )²+( $y_{2}$ - $y_{1}$ )²)

= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34

equation of circle is : (x+2)²+(y-5)² = 34

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3 years ago

What are the additive and multiplicative identities for any rational number

abruzzese [7]

Step-by-step explanation:

natural numbers, whole numbers, and integers zero is the additive identity
1 is the multiplicative identity.

in case of rational numbers.

<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>

6 0

2 years ago