CAN SOMEONE HELP ME WITH THIS PLEASE I NEED THIS BY TONIGHT!!!!

Mathematics

2 answers:

attashe74 [19]3 years ago

5 0

The value of the car after 3 years is $3,500

Ray Of Light [21]3 years ago

4 0

Answer:

$3500, y= 5000-500x

Step-by-step explanation:

You initially have $5000 which you then subtract $500 from each year, where x represents the number of years that passed.

y= 5000-500x

So after 3 years, it should be

y= 5000-500(3)

=5000-1500

=$3500

You might be interested in

Write a polynomial that has a GCF of 7m and another with a GCF of 2ab squared.

SVEN [57.7K]

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

<h3>Writing Polynomials </h3>

From the question, we are to write a polynomial that has a GCF of 7m

That is,

We are to write a polynomial that has a greatest common factor of 7m

<em>Writing the polynomial</em>

14mn - 21m + 49m²n + 7mn²

The polynomial above has a greatest common factor of 7m. That is, 7m is the greatest factor that can divide each of the terms

We are to write a polynomial with a GCF of 2ab²

<em />

<em>Writing the polynomial</em>

6a²b² - 8ab³ + 4a³b² + 2a³b³

The polynomial above has a greatest common factor of 2ab². That is, 2ab² is the greatest factor that can divide each of the terms

Hence,

The polynomial that has a GCF of 7m is 14mn - 21m + 49m²n + 7mn²

The polynomial that has a GCF of 2ab² is 6a²b² - 8ab³ + 4a³b² + 2a³b³

Learn more on Writing polynomials here: brainly.com/question/4525973

#SPJ1

7 0

1 year ago

CALC BC HELPPP!!!??? 100PTS!!!

lyudmila [28]

the assumption being that "x" is a plain variable whilst "y" is a function, that matters because the chain rule would be needed for a function, not so for a plain variable.

$4x^2+4x+xy=5\implies 8x+4+\stackrel{\textit{product rule}}{\left( 1\cdot y+x\cdot \cfrac{dy}{dx} \right)}=0 \\\\\\ x\cfrac{dy}{dx}=-8x-4-y\implies \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x}$

now, we know that y(5) = -23, which is another way of saying that when x = 5, y = -23, but we already knew that, we can get that by simply plugging it into the equation hmmm y'(5), well

$\left. \cfrac{dy}{dx}=\cfrac{-8x-4-y}{x} \right|_{\stackrel{x=5~}{\textit{\tiny y=-23}}}\implies \cfrac{-8(5)-4-(-23)}{5}\implies \cfrac{-21}{5}$